Answer:
The time required for sucrose transportation through the tube is 8.4319 sec.
Explanation:
Given:
L = 0.025 m
A = 6.5×10^-4 m^2
D = 5×10^-10 m^2/s
ΔC = 5.2 x 10^-3 kg/m^3
m = 5.7×10^-13 kg
Solution:
t = m×L / D×A×ΔC
t = (5.7×10^-13) × (0.025) / (5×10^-10)×(6.5×10^-4)×(5.2 x 10^-3)
t = 8.4319 sec.
Mass of the milkyway galaxy :
The magnitude of the mass of the Milky Way galaxy = 
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Answer:
the net work done on the cart is 160 J.
Explanation:
Given;
mass of the cart, m = 5.0 kg
initial velocity of the cart, u = 6 m/s
final velocity of the cart, v = 10 m/s
The net work done on the cart is equal to change in average kinetic energy of the cart;
Therefore, the net work done on the cart is 160 J.
Answer:
Explanation:
Given: Density of blood = 1.03 × 10³ Kg/m³, Height = 1.93 m g = 9.8 m/s²
pressure at the brain is equal to atmospheric pressure. = Hydro-static
pressure(ρ₀)
∴ pressure of the foot = pressure of the brain(ρ₀) + ( density of blood × acceleration due to gravity × height)(ρgh)
Hydro-static pressure = pressure at the feet- pressure at the brain(ρ₀)
Hydro-static pressure (Δp) = (ρgh + ρ₀) - ρ₀ = ρgh
Hydro-static pressure = 1.03 × 10³ × 9.8 × 1.93 = 1.948 × 10⁴ Pa
∴ Hydro-static pressure ≈ 1.95 × 10⁴ Pa
Answer:
a) Mat swum 100 meters.
b)after 4 length , Mat's displacement is zero.
Explanation:
As given, Mat and David are training for the swimming team , and Length of 1 side of the pool is 25 meter.
As swimming pool will be a cube or a cuboid , so it has only 4 sides.
a)
1 length = 23 meter
⇒4 length = 4×25 = 100 meter
So, Mat swam 100 meters.
b)
As after swam 4 lengths of the pool, Mat reaches to its initial position i.e Mat come back to its starting point.
As Displacement is always measures from the starting point.
So, after 4 length , Mat's displacement is zero.
