Answer:
E= 55.53 x 10³ V/m
Explanation:
Given that
a= 3.63 cm
Area ,A= a²
distance ,d= 0.473 mm
Stored energy ,U = 8.49 nJ
Value of capacitor given as
By putting the values
C=2.46 x 10⁻¹¹ F
V=Voltage difference
V=26.27 V
V= E d
E=Electric filed
26.27 = E x 0.473 x 10⁻³
E= 55.53 x 10³ V/m
If there is no existence of capacitors in our world there would be no electrical or electronic engineering.
A capacitor is a device that stores electrical energy in an electric field. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect. A capacitor commonly referred to as a condenser is one of the fundamental parts needed to create electronic circuits. Without fundamental parts like resistors, inductors, diodes, transistors, etc., a circuit's design is incomplete or it won't work properly.
Energy storage is capacitors' most popular application. Power conditioning, signal coupling or decoupling, electronic noise filtering, and remote sensing are further applications. Capacitors are employed in a wide variety of industries and have integrated into daily life due to their numerous applications.
There are numerous significant uses for capacitors. They are employed in digital circuits, for instance, to prevent the loss of data saved in big computer memories during a brief loss of power. The electric energy held in such capacitors keeps the data from being lost during a brief power outage.
To know more about capacitors refer to: brainly.com/question/14126841
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Answer:
Explanation:
(Assuming the cell in the circuit has 0 internal resistance)
Ohm's Law is given as:
Voltage is Current multiplied by Resistance.
We can rearrange this formula to give us:
Now we can plug in our values
"Gauss's Law. The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field. ," Source: <span>hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html
If you would like more info please look at the website. Im only in middle school, so I am sorry if this is not what you were looking for.....</span>
