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lesya692 [45]
3 years ago
12

In the diagram the figures are similar what is x

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0
There is no diagram shown. >.>
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Write an equation of the line that passes through the points<br> (0, 3) and (-5, 0).
Setler [38]

Answer:

y-3=3/5x

Step-by-step explanation:

y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=(y2-y1)/(x2-x1)

m=(0-3)/(-5-0)

m=-3/-5

m=3/5

y-3=3/5(x-0)

y-3=3/5(x)

y-3=3/5x

5 0
3 years ago
Read 2 more answers
Please help me!!! I don’t know how to do this
Amanda [17]

Answer:

37.5°

Step-by-step explanation:

Since RST are congruent to SRQ, then SRQ is 37.5°

Hope that helps!

5 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 208 days and a standard deviation of 15 days. A wife claimed
IrinaVladis [17]

Answer:

0%

Step-by-step explanation:

We have the following information:

mean (m) = 208 days

standard deviation (s) = 15 days

We have that the z value would be:

z = (x - m) / sd

replacing we have:

z = (308 - 208) / 15

z = 6.66

However,

P (x> 308) = 1 - (x <308)

P (x> 308) = 1 - (z <6.66)

if we look for this value of z in the table we assume that it is 1, since the table reaches 3 and the value is 1. Therefore:

P (x> 308) = 1 - 1

P (x> 308) = 0

Which means that the probability is 0%, therefore it is a very unusual pregnancy.

5 0
4 years ago
The following statements concern the modulus. Which statement is false?
Gelneren [198K]

we will check each options

option-A:

The modulus represents the distance between the complex number and the origin

we know that modulus is a kind of distance

For example: if we have to find modulus of x+iy

we get

|z|=\sqrt{x^2+y^2}

that is also distance between (0,0) and (x,y)

so, this is TRUE

option-B:

|z|=\sqrt{x^2+y^2}

It is also similar to Pythagoras theorem

so, this is also TRUE

option-C:

we got modulus formula

|z|=\sqrt{x^2+y^2}

we know that value of sqrt can never be negative because it will always result in positive value

so, this is FALSE

option-D:

|z|=\sqrt{x^2+y^2}

It is also similar to absolute value

so, this is TRUE

5 0
3 years ago
Factorise 1-a^2 b^2​
DerKrebs [107]

Hi there.

Thanks for using Brainly!

First, let's rewrite to make this problem easier.

1^2 - a^2b^2

Then we must multiply the terms with equal exponents with their bases.

1^2-(ab)^2

Using the factor: a^2 - b^2=(a-b)(a+b)

We can factor using that expression.

(1-ab) x (1+ab)

After factoring, this has been our solution.

Solution: (1-ab) x (1+ab)

Thanks for using Brainly!

- Tutor John

7 0
3 years ago
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