All categories

3 years ago

(1/216)^(x+2)=6^12 Solve for X

1 answer:

7 0

Log(1/216)^(x+2) = log 6^12

(x+2) log(1/216) = log 6^12

xlog(1/216) + 2log(1/216) = log6^12

xlog(1/216) = log6^12 - 2log(1/216)

x = [log6^12-2log(1/216] / log(1/216)

x = -6

You might be interested in

What is 25 over 80 written as a decimal

hram777 [196]

.3125 is equal to 25/80

6 0

3 years ago

Draw to show regrouping. Write how many tens and ones in the sum. Write the sum. This has me so confused.

olya-2409 [2.1K]

I am not sure, but we're you going to put up a sum.

7 0

3 years ago

What is the rule that defines the function shown in the graph for the interval, {-2 < x < 0}?

KIM [24]

Answer:

Step-by-step explanation:

720,080 in expanded form with components

(7 X 10>50

3 0

2 years ago

Suppose Maya made another sign with an area of 48 square inches. Would this sign be larger or smaller than the sign with an area

luda_lava [24]

Larger because I want the points and you are going to get an F

6 0

3 years ago

Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

Let $\mu$ = mean contents of cola bottles.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 300 ml {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, $H_A$ : $\mu$ < 300 ml {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean contents of cola bottle = $\frac{\sum X}{n}$ = 299.03 ml

$\sigma$ = population standard deviation = 3 ml

n = sample of bottles = 6

So, test statistics = $\frac{299.03-300}{\frac{3}{\sqrt{6} } }$

= -0.792

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

8 0

3 years ago