Answer:the nth term of the sequence, Tn= -3n +12
Step-by-step explanation:
The nth term of an arithmetic progression is given as
Tn= a+ (n-1) d
where a= first term
and d = common difference
In this sequence, 9, 6 ,3 ,0, -3, -6 we can see that the number is decreasing by 3
The first term, a= 9
and common difference, d = -3
using our formulae
Tn= a+ (n-1) d
Tn= 9 + ( n-1) -3
Tn=9- 3n+ 3
Tn= -3n +12
Please use * to denote mult. here, not "x." "x" is your variable and cannnot also be a symbol for mult.
f(x)g(x) = 3x^3 - 5x^2.
Now let x = 3:
(f*g)(3) = 3(3)^3 - 5(3)^2 = 81-45 = 36 (answer)
Answer:
Step-by-step explanation:
10