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Marrrta [24]
3 years ago
12

The seventh term of an arithmetic sequence is 10.2 and the twelfth term is 17.7. What is the common difference of the arithmetic

sequence? The common difference is
Mathematics
2 answers:
Anna [14]3 years ago
8 0

Answer:

the common difference = 1.5

Step-by-step explanation:

The seventh term of an arithmetic sequence is 10.2 and the twelfth term is 17.7

a7 = 10.2

a12= 17.7

Use the formula for nth term

a_n= a_1+(n-1)d

where 'd' is the common difference

n is the number of terms

a1 is the first term

a_7= a_1+(7-1)d

10.2= a_1+6d  ---> equation 1

a_12= a_1+(12-1)d

17.7= a_1+11d  -------------> equation 2

Subtract equation 2 - equation 1

17.7= a_1+11d

10.2= a_1+6d

---------------------------------------

  7.5 = 5d

divide by 5 on both sides

d= 1.5

So the common difference = 1.5

marshall27 [118]3 years ago
3 0
7 = 10.2
12 = 17.7
Let's take 
d = 17.7 - 10.2/ 12 - 7
d =  7.5/ 5
d = 1.5
The common difference is 1.5

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What is the y intercept of a graph containing the two points (3,1) and (7,-2)?
olasank [31]

The y intercept of a graph containing the two points (3,1) and (7,-2) is \frac{13}{4}

<em><u>Solution:</u></em>

Given points are (3, 1) and (7, -2)

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

Where, "m" is the slope of line and "c" is the y intercept

<em><u>Let us first find the slope of line</u></em>

The slope of line is given as:

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Here the points are (3, 1) and (7, -2)

(x_1, y_1) = (3, 1)\\\\(x_2, y_2) = (7, -2)

Substituting in formula, we get

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To find the y intercept:

\text{Substitute } m = \frac{-3}{4} \text{ and } (x, y) = (3, 1) \text{ in eqn 1 }

1 = \frac{-3}{4} \times 3 + c\\\\1 = \frac{-9}{4} + c\\\\ \text{Simplify the above equation } \\\\1 = \frac{-9+4c}{4}\\\\4 = -9 + 4c\\\\13 = 4c\\\\\text{Divide both sides by 4 }\\\\c = \frac{13}{4}

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3 years ago
Point A is at (3, -8) and point B is at (7, 3). What is the midpoint of line segment AB?​
allochka39001 [22]

Answer:

(5, -5/2)

Step-by-step explanation:

The midpoint of any line segment is the average of the x- and y-values of the two endpoints.

Therefore, the midpoint of AB is ((3+7)/2, (-8+3)/2)=(10/2, -5/2)=(5, -5/2).

So, the answer is \boxed{(5, -5/2)} and we're done!

5 0
3 years ago
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