3 years ago

1. which of the following is true and radio waves?

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Number one is A. Two is D and I think three is A ( I'm not entirely sure about the last one)

You might be interested in

What is the measure of PSQ in degrees? Angle PSR measures 99°.

11111nata11111 [884]

we know that

Step 1

Find the value of x

m∠PSR= $99$ °

m∠PSR= $(3x+18)+(9x-27)$ °

$99 =(3x+18)+(9x-27) \\ 99=12x-9\\ 12x=108\\ x=9degrees$

Step 2

Find the value of m∠PSQ

m∠PSQ= $(3x+18)$

m∠PSQ= $(3*9+18)$

m∠PSQ= $45$ °

therefore

the answer is the option

C) 45 degrees

8 0

3 years ago

Read 2 more answers

Bianca uses 1/3 of clay to make 4 bowls. She uses the same amount of clay for each bowl. How much clay does Bianca use for each

kkurt [141]

Answer:

1/12clay each bowl

Step-by-step explanation:

Since we know she used 1/3, simply divide 1/3 by 4 to get your answer.

1/3 / 4/1

1/3 * 1/4

1/12

8 0

2 years ago

What is the unit rate of 1/4 kilometer in 1/3 hour

Sever21 [200]

Answer:

0.75km/h

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The expression 60 ⋅ 1. 2 t 60⋅1.2 t 60, dot, 1, point, 2, start superscript, t, end superscript models the number of nano-relate

mamaluj [8]

Answer:

B. There were 60 nano-related patents granted in 1991

Step-by-step explanation:

In the expression:

60⋅1.2^t

t is years after 1991, that is, in the year 1993, t = 2

60 is the value of the expression at t = 0, then it represents the amount of nano-related patents granted in 1991

5 0

3 years ago

Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thiev

erik [133]

Answer: Probability that both the pirate and the Captain hit each other's ships is $\frac{1}{9}$

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

$\frac{4}{9}$

Probability that the pirate hits the Captains's ship is given by

$\frac{1}{4}$

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship" is given by

$P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}$

Hence, probability that both the pirate and the Captain hit each other's ships is $\frac{1}{9}$

6 0

3 years ago