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gregori [183]
3 years ago
12

Find the surface area of the regular hexagonal pyramid shown to the nearest square meter. a. 406 m2 b. 393 m2 c. 819 m2 d. 240 m

2
Mathematics
1 answer:
elena-s [515]3 years ago
8 0

Answer is A. 406m2 so there is the answer to anyone who comes across this.

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What is the 103rd term of the arithmetic sequence
UNO [17]

Answer:

option B: 31/4

Step-by-step explanation:

Given

-3/4, -2/3 , -7/12, -1/2...........

General formula for arithmeti sequence to find nth term is

a_n = a_1 + (n-1) d

first term a_1 = -3/4

We find out common difference 'd'

Lets find the difference of first two terms

\frac{-2}{3} -\frac{-3}{4} = \frac{-8}{12} +\frac{9}{12} =\frac{1}{12}

common difference is 1/12

now we need to find 103rd term

a_n = a_1 + (n-1) d

First term is -3/4, d= 1/12

a_{103} = \frac{-3}{4}+(103-1)\frac{1}{12}

a_{103} = \frac{-3}{4}+(102)\frac{1}{12}

a_{103} = \frac{-3}{4}+\frac{34}{4}

a_{103} = \frac{-3+34}{4}

a_{103} = \frac{31}{4}

5 0
3 years ago
Read 2 more answers
The price of a $250 cost increased by 7% last year. The coat is now on sale for one half off. What is the sale price
Semenov [28]

Answer:$133.75

Step-by-step explanation:

$250 is 100%

? is 107%

$2.5 is 1%

$267.50 is 107%

267.50/2=$133.75

5 0
3 years ago
Name a pair of factors that are both prime numbers and have a product of 21
never [62]
First you need to make a list of prime numbers that can only be divisible by 1 and itself.
here are examples of prime numbers: 1, 3, 5, 7, 9++
once you have a list of the prime numbers just pick all of them that add up to 21.
for example : a number divisible by only itself and one + another number divisible only by itself and one = 21
8 0
3 years ago
When two sides of scale weigh the same the scale will balance
chubhunter [2.5K]

Answer:

evenly

Step-by-step explanation:

personal experience with scales

6 0
3 years ago
Jonathan finds a piece of metal that is 2 1/5 inches thick. He files off 3/10 inch. He adds a protective covering to the metal t
Mama L [17]
<h2>Answer:</h2><h2>The final thickness of the metal = 2 inches.</h2>

Step-by-step explanation:

Jonathan finds a piece of metal that is 2\frac{1}{5}  inches thick.

The thickness of the metal = 2\frac{1}{5} = \frac{11}{5}

He files off \frac{3}{10}  inch,

the thickness becomes =  \frac{11}{5} - \frac{3}{10} = \frac{19}{10}

He adds a protective covering to the metal that is  \frac{2}{10}  inch thick.

the thickness becomes,  \frac{19}{10} + \frac{2}{10} = \frac{21}{10}

Then, he polishes the metal and removes an additional \frac{1}{10} inch.

The final thickness becomes, \frac{21}{10} - \frac{1}{10}  = 2 inches

5 0
3 years ago
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