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3 years ago

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Find the surface area of the regular hexagonal pyramid shown to the nearest square meter. a. 406 m2 b. 393 m2 c. 819 m2 d. 240 m

2

1 answer:

elena-s [515]3 years ago

8 0

Answer is A. 406m2 so there is the answer to anyone who comes across this.

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Determine which line is perpendicular to y = - 7/5x-2.

tatuchka [14]

Answer:

y = 5/7 x - 6

Step-by-step explanation:

For two lines to be perpendicular, the product of their slope must be -1

The slope of the given function is -7/5

Let the slope of the required function be m

m * -7/5 = -1

7/5 m = 1

7 = 5m

m = 5/7

The slope of the line perpendicular to the line is 5/7

The required equation (using any value of the y-intercept) is expressed as;

y = 5/7 x - 6

Note that the y-intercept value was assumed and any value can be used

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3 years ago

Solve equation <br> 0.3 :4=9:y

elixir [45]

Answer:

You should use photomath, it would be more easier for u. Oh, and by the watñy Y=12

3 0

3 years ago

A bag has 4 red balls and 4 balls, what is the probability of getting a red ball randomly.

Mkey [24]

Answer:

1/2

Step-by-step explanation:

4/8 are red. If you simplify that you get 1/2.

8 0

3 years ago

The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope

NARA [144]

Answer:

a) (i) $m = 2.22$ , (ii) $m = 2$ , (iii) $m = 2$ , (iv) $m = 2$ , (v) $m = 1.82$ , (vi) $m = 2$ , (vii) $m = 2$ , (viii) $m = 2$ ; b) $m \approx 2$ ; c) The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

$m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$

(i) $x_{Q} = 6.9$ :

$y_{Q} =\frac{2}{6-6.9}$

$y_{Q} = -2.222$

$m = \frac{-2.222 + 2}{6.9-7}$

$m = 2.22$

(ii) $x_{Q} = 6.99$

$y_{Q} =\frac{2}{6-6.99}$

$y_{Q} = -2.020$

$m = \frac{-2.020 + 2}{6.99-7}$

$m = 2$

(iii) $x_{Q} = 6.999$

$y_{Q} =\frac{2}{6-6.999}$

$y_{Q} = -2.002$

$m = \frac{-2.002 + 2}{6.999-7}$

$m = 2$

(iv) $x_{Q} = 6.9999$

$y_{Q} =\frac{2}{6-6.9999}$

$y_{Q} = -2.0002$

$m = \frac{-2.0002 + 2}{6.9999-7}$

$m = 2$

(v) $x_{Q} = 7.1$

$y_{Q} =\frac{2}{6-7.1}$

$y_{Q} = -1.818$

$m = \frac{-1.818 + 2}{7.1-7}$

$m = 1.82$

(vi) $x_{Q} = 7.01$

$y_{Q} =\frac{2}{6-7.01}$

$y_{Q} = -1.980$

$m = \frac{-1.980 + 2}{7.01-7}$

$m = 2$

(vii) $x_{Q} = 7.001$

$y_{Q} =\frac{2}{6-7.001}$

$y_{Q} = -1.998$

$m = \frac{-1.998 + 2}{7.001-7}$

$m = 2$

(viii) $x_{Q} = 7.0001$

$y_{Q} =\frac{2}{6-7.0001}$

$y_{Q} = -1.9998$

$m = \frac{-1.9998 + 2}{7.0001-7}$

$m = 2$

b) The slope at P (7,-2) can be estimated by using the following average:

$m \approx \frac{f(6.9999)+f(7.0001)}{2}$

$m \approx \frac{2+2}{2}$

$m \approx 2$

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

$y = m\cdot x + b$

Where:

$x$ - Independent variable.

$y$ - Depedent variable.

$m$ - Slope.

$b$ - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

$-2 = 2 \cdot 7 + b$

$b = -2 + 14$

$b = 12$

The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

7 0

3 years ago

Please help me !!!!!!

navik [9.2K]

Answer:

The answer is the roman numeral ||.

Step-by-step explanation:

If you use the equation $c = \sqrt{a^{2}+b^{2}$ you will find the only one that works is roman numeral ||. This equation is for right triangles.

8 0

3 years ago