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MAXImum [283]
4 years ago
15

39,13,8,10,2 The sum

Mathematics
2 answers:
Bumek [7]4 years ago
5 0

I thank is 156

Step-by-step explanation:

velikii [3]4 years ago
3 0
It would be 72 because you add them together
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The quadratic function f(x)=ax^2+4x+c has a maximum at the point (1, 9) . What are the values of a and c?
valina [46]

Answer: a = -2  and  c = 7

Step-by-step explanation:

(this answer uses some basic calculus)

We know that f'(x) = 2ax + 4, and since (1,9) is a maximum of f, then f'(1) = 0. That means 2a + 4 = 0, so \boxed{a = -2}. Then since f(1) = 9, we have -2(1)^2 + 4(1) + c = 9, so \boxed{c = 7}.

6 0
2 years ago
Read 2 more answers
Sara collected $135 in donations for the hospital. This represents 5 percent of total collected. How much did the class collect
PIT_PIT [208]

Answer:

$2,700

Step-by-step explanation:

Find the total donation amount by dividing 135 by 0.05:

135/0.05

= 2700

So, the class collected $2,700 in all

5 0
3 years ago
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The annual tuition and parent rating of 12 private schools is shown on the scatterplot. The schools are rated on a scale of 0 to
cestrela7 [59]

Answer:

DUDEEE WHO GAVE YOU THIS QUESTION "LOL"

4 0
2 years ago
Which equations represent the line shown in the graph?
Anarel [89]
One way to find out is to subsiute the points and find which ones are true

the points are (3,2) and (-2,-1)
subsiute 3 for x and 2 for y, then -2 for x and -1 for y

y-3=3/5(x-2)
2-3=3/5(3-2)
-1=3/5(1)
-3=3/5 false



-3x+5y=1
-3(3)+5(2)=1
-9+10=1
correct
try the other
-3(-2)+5(-1)=1
6+-5=1
true
one answe ris B

3/5x+1/5
this is incompleteso I can't solve it
maybe it was supposed to be 3/5x+1/5=y, but I don't know



y+1=3/5(x+1)
2+1=3/5(3+1)
3=3/5(4)
3=12/5
false

the answe ris B (maybe C but I con't know)
3 0
3 years ago
Read 2 more answers
Ball thrown straight up
Tema [17]

Answer:

x = 2

Step-by-step explanation:

H(x) = 64x - 16x²

<u>Find the value of x when the ball reaches its maximum height.</u>

<u />

Since the largest degree in this equation is two, this function represents a parabola. We can find the maximum height of the ball at the vertex of the quadratic.

In H(x) = 64x - 16x², rearrange the powers from greatest to least:

  • a = -16
  • b = 64
  • c = 0

Vertex: [-b/2a, f(-b/2a)]

Substitute a and b into the x-value of the vertex: -b/2a.

  • -(64)/2·(-16)
  • -64/-32
  • 2

The vertex of the parabola is at x = 2, with a maximum height of H(2).

6 0
3 years ago
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