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ruslelena [56]
3 years ago
14

Suppose the total weight of the fish caught stayed the same but instead of 100 fish caught during the weeklong fishing trip only

10 fish were caught. How would the weight of each fish change?
Mathematics
1 answer:
vampirchik [111]3 years ago
3 0
The weight of each fish would be 10 times the weight of the previous fish.

Assume that the first time, the weight was 500 lb.  Since there were 100 fish caught, each one would weigh 500/100 = 5 lb.

This time, however, only 10 fish were caught.  The weight is still 500 lb.  500/10 = 50 lb per fish.

50 = 5(10), so the weight is 10 times more.
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Sarah Goes To Dinner With 2 Of Her Friends. The Total Cost Of Dinner Is $61.92 Her Friends Pay 2/3 of the total cost. Exactly Ho
IceJOKER [234]

Answer:

$20.64

Step-by-step explanation:

if you cut 61.92 in to thirds

61.92/ 3= 20.64

so if Sarah's friends payed 2/3 of the bill Sarah herself payed 1/3 which is $20.64

5 0
3 years ago
The U.S. Department of Transportation provides the number of miles that residents of the75 largest metropolitan areas travel per
Leya [2.2K]

Answer:

a. The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88

b. The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

Step-by-step explanation:

a. According to the given data we have the following:

Buffalo residents mean=22.5

Standard deviation=8.4

n=50

Boston residents mean=18.6

Standard deviation=7.4

n=40

Hence, the point estimate is the difference of the means=22.5-18.6=3.9

The standard error=√((s1∧2/n1)+((s2∧2/n2))=√((8.4∧2/50)+(7.4∧2/40))=1.67

Therefore, the difference of miles=n1+n2-2=50+40-2=88

The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88.

b. The critical value of t at 95% confidence level and DoF=88 is 1.987

The interval:(x1-x2)+ (critical value* std error)

=3.9-(1.987*1.67),3.9+(1.987*1.67)

Difference between mean=(0.58171,7.21829)

The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

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3 years ago
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3 0
3 years ago
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Hey guys please help with both
podryga [215]
1/2 *(a+b)-(a-b)²
a=18, b=14
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answer D

answer B 
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5 0
3 years ago
8&gt;3+t/4 what is the answer​
salantis [7]

Answer:

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