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jok3333 [9.3K]
1 year ago
9

0.60 gal to 0.12 gal as a fraction

Mathematics
1 answer:
adell [148]1 year ago
6 0

Answer:

0.60 gal to 0.12 gal can be rewritten as:

\frac{0.60}{0.12} =\frac{0.6}{0.6(0.2)} =\frac{1}{0.2}

\frac{1}{0.2}*1=\frac{1}{0.2}*\frac{10}{10} =\frac{10}{2} =5

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melomori [17]
I can't help you on this because you don't have an actual answer
7 0
3 years ago
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A square pyramid and a cube have the same surface area don’t of each side of the base of the Square pyramid is 10 feet the width
o-na [289]

Answer:

The lateral height of the square pyramid is 5.8\ ft

Step-by-step explanation:

step 1

Find the surface area of the cube

The surface area of the cube is equal to

SA=6b^{2}

where

b is the length side of the cube

w have

b=6\ ft

substitute

SA=6(6^{2})=216\ ft^{2}

step 2

Find the lateral height of the square pyramid

we know that

the surface area of the square pyramid  is equal to

SA=B+4(\frac{1}{2}bh)

where

B is the area of the base

b is the base of the lateral triangle (base of the square)

h is the lateral height of the square pyramid

B=(10^{2})=100\ ft^{2}

SA=216\ ft^{2} -----> is the same surface that the cube

b=10\ ft

substitute the values and solve for h

216=100+4(\frac{1}{2}*(10)*h)

216-100=20h

h=116/20=5.8\ ft

6 0
3 years ago
HELP WILL GIVE BRANLIEST!!
antoniya [11.8K]

Answer:

on flipping a coin, we either get a heads or a tails and both the events are equally likely. So the probablity of getting a tails is 1/2.

Now

On rolling a die, we can get 6 possible outcomes(1,2,3,4,5,6)

But the favourable outcomes (an even number) are only 3. So the probablity of getting an even number is 3/6=1/2

In case. we have 2 events that need to occur together, we simply need to multiply their individual probablities to get the probablity of getting both the events together

So our required answer is

p(even number)× p(tails)= 1/2 × 1/2 = 1/4

Step-by-step explanation:

7 0
3 years ago
Find the estimates of x^2-x-2=3
Julli [10]

Answer:

x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

Step-by-step explanation:

Given

Quadratic equation is

x^2-x-2=3\\x^2-x-5=0

Roots of the quadratic equation ax^2+bx+c=0 are

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\

So, for the given equation roots are

x=\frac{1\pm\sqrt{(-1)^2-4(1)(-5)}}{2\cdot 1}\\x=\frac{1\pm\sqrt{21}}{2}\\so, x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

5 0
3 years ago
What is the answer to <br> F(x)=x+2
Dimas [21]

Answer:327e823

Step-by-step explanation:

7 0
4 years ago
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