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Levart [38]
3 years ago
8

Sarah Goes To Dinner With 2 Of Her Friends. The Total Cost Of Dinner Is $61.92 Her Friends Pay 2/3 of the total cost. Exactly Ho

w Much Does Sarah Pay ?
Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0

Answer:

$20.64

Step-by-step explanation:

if you cut 61.92 in to thirds

61.92/ 3= 20.64

so if Sarah's friends payed 2/3 of the bill Sarah herself payed 1/3 which is $20.64

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Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?
Vinvika [58]
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
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\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad  \qquad  \qquad  g(x)=x+1\\\\
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\textit{they're, kinda, except that, when x = 1}
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g(x)=(1)+1\implies g(x)=2
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f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined
7 0
3 years ago
Solve the inequality $-4x > -24.$ Give your answer in interval notation.
Scorpion4ik [409]

Answer:

x>6 that's means x is greater than 6

6 0
3 years ago
Yoko is going for a walk. She takes 5 hours to walk 12.5 miles. What is her speed?
Dennis_Churaev [7]

Answer:

2.5mph (miles per hour)

Step-by-step explanation:

Simple, 12.5/5 = 2.5 mph (miles per hour)

8 0
3 years ago
What is the solution to y=2/5x-3 and x=-10
Vanyuwa [196]

y is -2/53

Step-by-step explanation:

  • Step 1: Given equation is y = 2/5x-3 and x = -10. Substitute value of x to find the solution.

⇒ y = 2/(5 × -10 - 3) = 2/-53 = -2/53

4 0
3 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
3 years ago
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