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3 years ago

Talia bought a home for her pet turtle the rectangular tank is 3 feet long. 1 foot wide and 2 feet high. What is the volume?

Mathematics

2 answers:

Anna [14]3 years ago

4 0

Answer:

Step-by-step explanation:

Serggg [28]3 years ago

3 0

Answer:

Volume of rectangular tank = 6 cubic feet

Step-by-step explanation:

Length of the rectangular tank = 3 feet

Width of the tank = 1 feet

And height of the rectangular tank = 2 feet

Since, tank is in the shape of a cuboid,

Volume of a cuboid = Length × Width × height

= 3 × 1 × 2

= 6 cubic feet

Therefore, volume of the rectangular tank will be 6 cubic feet.

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What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the

jeyben [28]

Answer:

diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

(b-r) +(a-r) = c

(a+b) -2r = c

Now, the problem statement defines the sum of side lengths as ...

a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

m -d = c

m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0

3 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

3 years ago

2+3!!<br> Help!! Due in an hour!!

Zanzabum

Answer:

Step-by-step explanation:

I think

6 0

3 years ago

Read 2 more answers

How many times does 12 go into 60?

statuscvo [17]

Answer:

5 times

Step-by-step explanation:

3 0

3 years ago

the excursion boat on the river takes 2 1/2 hours to make the trip to a point 12 miles up stream and to return. If the rate at w

MissTica

Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C

Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C

Upstream time +downstream time:= 2h30 ' then:

12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h

4 0

3 years ago