Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
Answer:
5
Step-by-step explanation:
I think
Answer:
5 times
Step-by-step explanation:
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h