Answer:
The constant force exerted on the bullet is 1590.87 N.
Explanation:
It is given that,
Mass of the bullet, m = 8.6 g
Initial speed of the bullet, u = 0
Final speed of the bullet, v = 430.1 m/s
We need to find the force exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle. Let a is the acceleration of the bullet. So,
Let F is the force exerted. It is given by :
F = 1590.87 N
So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.
Answer:
The correct answer is C) The object will begin to move with a changing velocity
Explanation:
Newton's First Law indicates that "Every body perseveres in its state of rest or uniform rectilinear motion unless it is forced to change its state by forces impressed upon it." This means that for a body to come out of its state of rest or of uniform rectilinear motion (where the speed is constant), it is necessary for a force to act on it.
In Newton's first law, the forces are balanced as he perseveres in his state of rest or of uniform rectilinear motion. That is, the net force on the object is zero (that is, the result of the sum of all the forces is zero). When a force acts on a body, the body leaves its state of rest or of uniform rectilinear motion.
<u><em>Then, the correct answer is C) The object will begin to move with a changing velocity</em></u>
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