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Norma-Jean [14]
2 years ago
6

5. Based on the data collected by the students, what is the tangential velocity of

Physics
1 answer:
malfutka [58]2 years ago
8 0

The tangential velocity of the ball is 0.63 m/s.

<h3>What is tangential speed?</h3>

Tangential speed is the linear component of the speed of any object moving along a circular path.

v = ωr

where;

  • v is the tangential speed
  • ω is the angular speed (rad/s)
  • r is the radius of the circle

At a given radius of the circle = 0.3 m

Let the number of revolution per min = 20 rev/min

\omega = 20 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} = 2.1 \ rad/s

v = ωr

v = 2.1 x 0.3

v = 0.63 m/s

Thus, the tangential velocity of the ball is 0.63 m/s.

Learn more about tangential velocity here: brainly.com/question/25780931

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Distance = 44 m

Speed = 24 m/s

Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

u_{x}=u\cos\theta

Put the value into the formula

u_{x}=24\cos(31)

u_{x}=20.5\ m/s

We need to calculate the vertical velocity

Using formula of vertical velocity

u_{y}=u\sin\theta

Put the value into the formula

u_{y}=24\sin(31)

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We need to calculate the time

Using formula of time

t=\dfrac{d}{u_{x}}

Put the value into the formula

t=\dfrac{44}{20.5}

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We need to calculate the vertical height

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h=u_{y}t+\dfrac{1}{2}at^2

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Hence, The distance by the ball clear the crossbar is 1.15 m

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