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kolezko [41]
4 years ago
5

What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes

Physics
1 answer:
sp2606 [1]4 years ago
7 0
** Missing info: Lines per mm = 500 **

Ans: The wavelength is =  λ = 1414.21 nm

Explanation:
The formula for diffraction grading is:

dsinθ = mλ --- (1)

Where
d = 1/lines-per-meter = (1/500)*10^-3 = 2 * 10^-6
m = order = 1
λ = wavelength
θ = 45°

Plug in the values in (1):
(1) => 2*10^-6*sin(45°) = (1)λ
=> λ = 1414.21 nm
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The emission spectra you obtained from a star show a hydrogen spectrum that is shifted toward the blue end of the electromagneti
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Answer:

The correct option is;

The star is moving toward Earth.

Explanation:

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3 years ago
Scientists have investigated how quickly hoverflies start beating their wings when dropped both in complete darkness and in a li
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Answers:

A) 0.204 m

B) 0.285 s

Explanation:

<h2>Answer A:</h2>

This described situation is free fall, this means the initial velocity of the fly is zero, and the equation that will be used is:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y is the final height of the fly

y_{o}=40 cm=0.4 m is the initial height of the fly

V_{o}=0 is the initial velocity of the fly

t=200(10)^{-3} s is the time

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y=0.4 m+0-\frac{1}{2}(9.8 m/s^{2})(200(10)^{-3} s)^{2} (2)

y=0.204 m (3)  This is the distance at which the fly would begin to beat its wings

<h2>Answer B:</h2>

In this part we will also use equation (1), but we will find the time:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 is the final height of the fly

y_{o}=40 cm=0.4 m is the initial height of the fly

V_{o}=0 is the initial velocity of the fly

t is the time  we need to find

g=9.8 m/s^{2} is the acceleration due to gravity

0=0.4 m+0-\frac{1}{2}(9.8 m/s^{2})t^{2} (4)

Isolating t:

t^{2}=\frac{(-2)(-0.4 m)}{9.8 m/s^{2}} (5)

t=0.285 s (6)  This is the time it would take for a fly to hit the bottom of the box

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4 years ago
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