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4 years ago

5

What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes

1 answer:

sp2606 [1]4 years ago

7 0

** Missing info: Lines per mm = 500 **

Ans: The wavelength is = λ = 1414.21 nm

Explanation:
The formula for diffraction grading is:

dsinθ = mλ --- (1)

Where
d = 1/lines-per-meter = (1/500)*10^-3 = 2 * 10^-6
m = order = 1
λ = wavelength
θ = 45°

Plug in the values in (1):
(1) => 2*10^-6*sin(45°) = (1)λ
=> λ = 1414.21 nm

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