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Aleksandr [31]
3 years ago
13

I will give extra points if u will help with this

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
4 0
A. isosceles and acute

hope this helps :)
pogonyaev3 years ago
4 0
The answer is B isosceles and obtuse
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The answer is c 40 km
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3 years ago
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Can someone explain how to do
Alinara [238K]

The solution is:

3\leq y\leq 10

Or

y ≥ 3 and y≤10

Further explanation:

The given inequality is compound inequality which is solved in two parts.

Given inequality is:

10 \leq 2y+4\leq 24

The two inequalities which will be formed are:

2y+4\geq 10\\2y+4\leq 24

Solving one by one

2y+4\geq 10\\2y+4-4\geq 10-4\\2y\geq 6\\\frac{2y}{2} \geq \frac{6}{2} \\ y \geq 3\\2y+4\leq 24\\2y+4-4\leq 24-4\\2y\leq 20\\\frac{2y}{2}\leq \frac{20}{2} \\y\leq 10

The solution is:

3\leq y\leq 10

Or

y ≥ 3 and y≤10

Keywords: Inequalities, Compound inequalities

Learn more about inequalities at:

  • brainly.com/question/6703816
  • brainly.com/question/10402163

#LearnwithBrainly

8 0
4 years ago
The expression 6x - 3 represents the total number of stuffed animals Deena has in her collection. She decides to put the
jeyben [28]

Answer:

2x-1 (simplest)

Step-by-step explanation:

First put parentheses around 6x-3

The expression is (6x-3)/3

Simplify 2x-1

Make sure you divide both terms though (common mistake only dividing 1)

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3 years ago
∆ABC is similar to ∆DEF. The ratio of the perimeter of ∆ABC to the perimeter of ∆DEF is 1 : 10. The longest side of ∆DEF measure
nikdorinn [45]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{\triangle ABC}{\triangle DE F}\qquad \cfrac{longest\ side}{longest\ side}\quad \cfrac{1}{10}=\cfrac{40}{s}\implies s=\cfrac{10\cdot 40}{1}\\\\
-------------------------------\\\\
\cfrac{\triangle ABC}{\triangle DE F}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}\implies \cfrac{1}{10}=\cfrac{\sqrt{A_1}}{\sqrt{A_2}}\implies \cfrac{1}{10}=\sqrt{\cfrac{A_1}{A_2}}
\\\\\\
\left( \cfrac{1}{10} \right)^2=\cfrac{A_1}{A_2}\cfrac{1^2}{10^2}=\cfrac{A_1}{A_2}\implies \cfrac{1}{100}=\cfrac{A_1}{A_2}
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What is the answer to this question. PLEASE HELP
OLEGan [10]

Answer:

Im going to guess a i have no idea tho

Step-by-step explanation:

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