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3 years ago

What is the common denominator of 2/7 and 1/4

Mathematics

2 answers:

Anastasy [175]3 years ago

6 0

The common denominator is 28

Serjik [45]3 years ago

3 0

Answer:

Explanation :

Mutiply by 4 for 2/7 to get the denominator which is 28

(2)(4)/(7)(4)= 8/28

Mutiply by 7 for 1/4

(1)(7)/(4)(7)= 7/28

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What is the solution to the system of equations below?

Andre45 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

$y=-6x-10$

$y=-3x-21$

solving the system of the equations

Arrange the equation variables for elimination

$\begin{bmatrix}y+6x=-10\\ y+3x=-21\end{bmatrix}$

$y+3x=-21$

$-$

$\underline{y+6x=-10}$

$-3x=-11$

$\begin{bmatrix}y+6x=-10\\ -3x=-11\end{bmatrix}$

solve

$-3x=-11$

Divide both sides by -3

$\frac{-3x}{-3}=\frac{-11}{-3}$

$x=\frac{11}{3}$

$\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=\frac{11}{3}$

$y+6\cdot \frac{11}{3}=-10$

$y=-32$

Therefore, the solutions to the system of the equations are:

$y=-32,\:x=\frac{11}{3}$

But, it seems none of the options is true.

8 0

3 years ago

Read 2 more answers

PLEASE I'm DESPERATE!. Find a, b, c, and d such that the cubic . f(x) = ax3 + bx2 + cx + d. satisfies the given conditions.. Rel

dimulka [17.4K]

We are given with the equation f(x) = ax3 + bx2 + cx + d

Substituting, (3,11)
11= 27a + 9b + 3c + d
@(5, 9)
9 = 125 a + 25 b + 5c + d
@(4, 10)
10 = 64 a + 16 b + 4c + d

@inflection point, second derivative is equal to zero
f'(x) = 3ax2 + 2bx + c
f''(x) = 6ax + 2b = 0

when x is 4, 24 a + 2b = 0 or 12a + b = 0.

There are 4 equations, 4 unknowns: answer is
0.5 x^3 - 6x^2 + 22.5 - 24 = 0

4 0

3 years ago

Read 2 more answers

Can someone show me how to do this please

marta [7]

Answer:

$volume = 0.32 m^3$

Step-by-step explanation:

The object shown above consists of 5 cubes having side lengths of ⅖m each.

Volume of a cube = $a^3$

Where, a = side length = ⅖ m

Volume of the object = $5* (\frac{2}{5})^3$

$volume = 5*\frac{8}{125} = 5*0.064 = 0.32 m^3$

6 0

3 years ago

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

2 years ago

Helppppppp meeeeee plzzzz

bulgar [2K]

Non proportional I think. Wait for someone else to answer

8 0

2 years ago

What is the common denominator of 2/7 and 1/4​

What is the common denominator of 2/7 and 1/4