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3 years ago

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suppose a study estimated that 78% of the residents of a town (with an error range plus/minus12 percentage points at 95% confide

nce) favor building a new community center. which of the following percentages of the towns residents may favor building a new community center

2 answers:

diamong [38]3 years ago

6 0

Answer:

<em>The percentage is between </em><em>66% to 90%</em>

Step-by-step explanation:

Confidence Interval-

A confidence interval is the range of values we are fairly sure the true value will lie in that range or interval.

Mathematically, the range of confidence interval of a sample is,

$=\text{Average}\pm \text{Margin of error}$

or

$=\overline X\pm Z\dfrac{s}{\sqrt{n}}$

where,

$\overline X$ = is the mean

Z = Z-value of confidence interval

s = standard deviation

n = number of observations

Putting the values, confidence interval will be,

$=78\pm 12\\\\=66\%\ to\ 90\%$

Therefore, any percentage value in between 66% to 90% will be the percentages of the towns residents who may favor building a new community center.

abruzzese [7]3 years ago

4 0

the Answer is 69% -Apex

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4 years ago

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Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
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Neither
⊥
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Neither
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Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are <u>neither</u> parallel or perpendicular

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2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are <u>parallel</u>

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3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are <u>Neither</u> parallel nor perpendicular

<u>Neither</u>

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are <u>perpendicular</u>

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5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are <u>parallel</u>

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6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

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Therefore, the two equations are <u>neither</u> parallel nor perpendicular

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7. The equations are;

2·x + 6·y = -3

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Which gives

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Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

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Therefore, the slopes are not equal, or perpendicular, the correct option is <u>Neither</u>

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Answer:

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Ne4ueva [31]

Answer:

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Pvalue = 0.7482 ;

Fail to reject H0.

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H0 : μd = 0

H1 : μd ≠ 0

Given the data:

Before: 15 26 66 115 62 64

After: 16 24 42 80 78 73

Difference = -1 2 24 35 -18 -9

Mean difference, d ; Σd / n

d = Σx / n = ((-1) + 2 + 24 + 35 + (-18) + (-9))

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std = sample standard deviation = 20.146

Test statistic = 5.5 ÷ (20.146/sqrt(6))

Test statistic = 0.6687

The Pvalue :

P(Z < 0.6687) = 0.7482

At α = 0.05

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Answer:

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Step-by-step explanation:

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