Answer:
2 seconds
Step-by-step explanation:
In this question, we are asked to calculate the the number of seconds it will take for an object to reach its maximum height given the equation of motion of the object in question.
At maximum height, we must know that the instantaneous y velocity becomes equal to zero. Now looking at the equation of motion in the question, what we need to do
Is to differentiate it with respect to t so as to get the information for the velocity.
dh(t)/dt = -32t + 64
At maximum height dh(t)/dt = 0
Hence -32t + 64 = 0
32t = 64
t= 64/32 = 2 acquiring all the banks in Nigeria
It will only take two seconds to hit maximum height
Answer:
$26.03
Step-by-step explanation:
$234.27/9=$26.03
10% = 3
70% = 3 * 7
= 21 students
Jamall is wrong because 70% of the class = to 21 students.
Answer:
∠P = 39º
∠Q=120º
∠R = 21º
Step-by-step explanation:
m∠P+m∠Q+m∠R=180º (sum of ∠s in a triangle)
2x-3+6x-6+x=180º (substitution)
9x-9=180º (algebra)
9x=189º (algebra)
x=21º (algebra) (this is ∠R)
(2x-3)=39º (algebra) (this is ∠P)
6x-6=120º (algebra) (this is ∠Q)
