Question

a 23 gram sample of a substance thats a by-product of fireworks has a K-value of .13. whats the substances half life in days

Answer 1

Answer:

5.3 is the right answer.

Step-by-step explanation:

Answer 2

Given:
Initial mass, m₀ = 23 g
Decay constant, k = 0.13

Exponential decay obeys the equation
$m(t)=m_{0} e^{-kt}$
where t = time, days

For half life, the mass is m = m₀/2.
Therefore
$e^{-0.13t} = \frac{1}{2} \\ -0.13t = ln(0.5)\\t= \frac{ln(0.5)}{-0.13} =5.33$

Answer: The half life is 5.33 days