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melisa1 [442]
3 years ago
5

Solve equation a+6a-9=30

Mathematics
1 answer:
ra1l [238]3 years ago
8 0
A=5 4/7 or 5.57142857143 
I cannot be simplified any more
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Help???????????!!!!!!!!!!!
Butoxors [25]
Salutations!

12 \frac{2}{3}

- 9 \frac{3}{4}

= \frac{38}{3} 

Then,

- 9 \frac{3}{4}

- \frac{39}{4}

Next, our final answer:

= \frac{35}{12}

= 2 \frac{11}{12} 

Our decimal would be 2.916667

Hopefully This Helps!!!

 
3 0
3 years ago
Help pls, this is geometry
Talja [164]

Answer:

sas - meaning side angle side

Step-by-step explanation:

7 0
3 years ago
What is the difference? 14x over 17 minus 3x over 17 (14x/17 - 3x/17)
Gre4nikov [31]
14x-3x= 11x and the 17 stays the same, so the answer is 11x/17 or answer B.

7 0
3 years ago
Graph ​ y−5=−23(x+9) ​ using the point and slope given in the equation.
Mashcka [7]

Answer:

Plot (-9,5) then you do rise over run and go down 2 and to the right 3

Step-by-step explanation:

So your points would  be (-9,5) and(-6,3)

6 0
3 years ago
The national average for the number of students per teacher for all U.S. public schools in 15.9. A random sample of 12 school di
Nady [450]

Answer:

The 95% confidence interval for the true mean number of students per teacher is (17.9, 20.5). The lower bound of the interval is above the national average, which means that this estimate is higher than the national average.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 12 - 1 = 11

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 11 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.201

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.201\frac{\sqrt{4.41}}{\sqrt{12}} = 1.3

In which s is the standard deviation of the sample(square root of the variance) and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 19.2 - 1.3 = 17.9 students.

The upper end of the interval is the sample mean added to M. So it is 19.2 + 1.3 = 20.5 students

The 95% confidence interval for the true mean number of students per teacher is (17.9, 20.5). The lower bound of the interval is above the national average, which means that this estimate is higher than the national average.

5 0
3 years ago
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