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Levart [38]
4 years ago
10

Expand a logarithmic expression

Mathematics
2 answers:
ivanzaharov [21]4 years ago
8 0

The logarithmic expression is

log (\sqrt{z^5}/(x^3y))

To expand the expression we have to use some properties of logarithm.

We know that log(m/n) = log (m) - log(n)

By using this property we can write,

log(\sqrt{z^5}) - log(x^3y)

Square root means to the power 1/2, so for \sqrt{z^5}, we can write z^(5/2).

log(z^(5/2)) - log(x^3y)

Now we have to use another property of logarithm.

We know that, log(mn) = log(m) + log(n)

So we will use this property to log(x^3y)

log(z^(5/2)) - log(x^3y)

log(z^(5/2)) - (log(x^3) + log(y))

log(z^(5/2)) - log(x^3) - log(y)

Now we have to use another property of logarithm.

We know that, log(a^m) = m log(a)

By using this property we can write,

(5/2)log(z) - 3log(x) - log(y)

This is the required aswer here.

irinina [24]4 years ago
7 0

we have logarthmic division function .

log(\frac{\sqrt{z^5}}{x^3y}  )

we know that log(a/b)=log a-log b

so the given function will be log(\sqrt{z^5} )-log(x^3y)=\frac{5}{2} logz-(3logx+logy)

we know that if a exponent in log is bought down it will be multiplied with log

so we got square root of z^5 and x^3 as 5/2 and 3 .

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3 0
3 years ago
Read 2 more answers
Please help with all 3
DerKrebs [107]

Answer:

1, volume=23×9×5

=1035

2, volume=(1/2×5×4)×20

... =200

3.

8 0
3 years ago
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A gym membership is $100 sign-up fee and charges $20 a month thereafter. How much is the membership fee in a month?
trapecia [35]

Answer:

$120

Step-by-step explanation:

y = mx + b

The $100 sign up fee is a set amount, or the b value.

The $20 would be the m value since it the constant change, or the slope.

Thus, the equation would be y=20x + 100

The membership fee for 1 month would be --->

y= 20(1) +100

y= 20 + 100

y= $120

                                     

4 0
3 years ago
Let (3, -2) be a point on the terminal side of 0.
saveliy_v [14]

Answer:

sinθ = -0.554

tanθ = -0.667

secθ = 1.203

Step-by-step explanation:

Consider the point (3, -2)

The value of x is positive and the value of y is negative.

It means the the terminal sides of angle lies in 4rth quadrant, such that:

Base = 3

Perpendicular = 2

Hypotenuse² = 2² + 3²

Hypotenuse =  3.61

sinθ = Perpendicular /Hypotenuse

sinθ = 2/3.61

As sine is negative in 4rth quadrant

sinθ = - (2/3.61)

sinθ = -0.554

tanθ = Perpendicular/ Base

tanθ = 2/3

tanθ = 0.667

As tan is negative in 4rth quadrant

tanθ = -0.667

secθ = Hypotenuse/Base

secθ = 3.61/3

secθ = 1.203

secant is positive in 4rth quadrant

3 0
3 years ago
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