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irina1246 [14]
3 years ago
5

Identify whether each of these functions contains a minimum or a maximum

Mathematics
1 answer:
iogann1982 [59]3 years ago
7 0

Answer:

I graphed the functions on the graph below.

Step-by-step explanation:

1) Minimum

2) Maximum

3) Minimum

4) Maximum

If these answers are correct, please make me Brainliest!

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Solve the equation for y (picture below)<br> Please show work and solve as much as you can
Alina [70]
2)
4x-10y=12

Subtract 4x from each side.
-10y=-4x+12

Divide both sides by -10
y=2/5x-6/5

3)
13=1/6y+2x

Subtract 2x from each side.
-2x+13=1/6y

Multiply both sides by 6.
-12x+78=y

Flip it around.
y=-12x+78

Hope this helps!
5 0
3 years ago
the providence children muesuem installed a fence around the perimeter of the propety. the propety is a rectangle. one side is 3
mash [69]
Its a rectangle so two sides are equal and both sides that are opposite of each other are equal. So two sides are 37. Then you add them together to get 74, then subtract it from 164 to get 90 the rest of the fence length. Then divide it by two to get 45 which is the other side lengths, so it would be a 37 by 45 rectangle one side would be 37 while the other two are 45.
7 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
Solve this equation 11/20 +x= 9/10
Sav [38]

Answer:

7/20

Step-by-step explanation:

\frac{11}{20}+x=\frac{9}{10} \\x=\frac{7}{20}

7 0
3 years ago
Read 2 more answers
Difference of squares examples
bazaltina [42]
Triangle, rectangles, pollygon, robtuse, i hope this is what you mean

8 0
3 years ago
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