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Angelina_Jolie [31]
3 years ago
15

If the sum of five consecutive even integers is 90, what is the smallest of the five integers?

Mathematics
1 answer:
ruslelena [56]3 years ago
5 0

So the pattern of even integers is: 2, 4, 6, 8, etc. They are always 2 more than the prior even integer. Using this knowledge, our 5 consecutive even numbers are (let x = smallest even number): x, x + 2, x + 4, x + 6, and x + 8.

Now that we have the numbers, we can form our equation as such: x+x+2+x+4+x+6+x+8=90 . From here we can solve for x.

Firstly, combine like terms: 5x+20=90

Next, subtract 20 onto both sides of the equation: 5x=70

Lastly, divide both sides by 5 and <u>your smallest integer is x=14</u>

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0-2
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————
-2
y=5
hope this helps
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3 years ago
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saveliy_v [14]

Answer:

Y =2X +2

y = 2(13) + 3

y = 29 after 13 months

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3 years ago
A n-faced regular polyhedron consists of 2n edges and (2n-4) vertices. Find n .
ira [324]

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3 years ago
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