So the pattern of even integers is: 2, 4, 6, 8, etc. They are always 2 more than the prior even integer. Using this knowledge, our 5 consecutive even numbers are (let x = smallest even number): x, x + 2, x + 4, x + 6, and x + 8.
Now that we have the numbers, we can form our equation as such:
. From here we can solve for x.
Firstly, combine like terms: 
Next, subtract 20 onto both sides of the equation: 
Lastly, divide both sides by 5 and <u>your smallest integer is
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