Answer:
8 seconds
Step-by-step explanation:
Given
h = - 5t² + 40t
When the object hits the ground then h = 0
Substitute h = 0 into the function and solve for t
- 5t² + 40t = 0 ← factor out - 5t from each term
- 5t(t - 8) = 0
Equate each factor to zero and solve for t
- 5t = 0 ⇒ t = 0
t - 8 = 0 ⇒ t = 8
t= 0 denotes the time of launch
t = 8 denotes the time it hits the ground
Answer:
a = 5 1/3
Step-by-step explanation:
a+b+b = 24
a + 2b = 24
b-a =4
a = b - 4
b - 4 + 2b = 24
3b = 24 + 4
b =28/3
substitute this in a = b - 4
a = 28/3 - 4
a = 28/3 - 12/3
a = 16/3
a = 5 1/3
Answer:
the first one is right and other are wrong
Answer:
y=16x ??
Step-by-step explanation:
Answer:
a=-26,b=-10,c=-1,d=-2
Step-by-step explanation:
when x=-3
y=-(-3)^2 +4(-3)-5=a
a=-9-12-5
=-14-12
=-26
when x=-1
y=-(-1)^2 +4(-1)-5=b
=-1-4-5
b=-10
when x=2
y=-(2)^2 +4(2)-5=c
=-4+8-5
=-9+8
c=-1
when x=3
y=-(3)^2 +4(3)-5=d
=-9+12-5
=-14+12
d=-2
