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sasho [114]
3 years ago
8

1/2x +8/4 ≤ 4 Solve the inequality for X

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

x ≤ 4

Step-by-step explanation:

Given

\frac{1}{2} x + \frac{8}{4} ≤ 4 , that is

\frac{1}{2} x + 2 ≤ 4 ( subtract 2 from both sides )

\frac{1}{2} x ≤ 2 ( multiply both sides by 2 to clear the fraction

x ≤ 4

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Y = 4x - 2<br> y = x + 3
arlik [135]

Answer:

y=3x+1

Step-by-step explanation:

if im correct you are working on elimination, so you pretty much sub. so the difference between -2 and 3 is positive 1; the difference between 4x and x is 3x

are you working on elimination?

8 0
3 years ago
14. (2a^4)^3 <br> what is the answer to this?
MariettaO [177]

Answer: The answer is 6.

Step-by-step explanation:

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kozerog [31]

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c

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3 years ago
96g + 80f and explain
iragen [17]

Answer:

Combine Like Terms, Use Distributive Property Worksheet. Fact or Fiction: Factorials Have Nothing to Do With Factoring. Simplify. 1. 4xy + 3x2y - 3xy + 2x2y .

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3 years ago
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Suppose that in a random selection of 100 colored​ candies, 24​% of them are blue. The candy company claims that the percentage
LuckyWell [14K]

Answer:

We conclude that the percentage of blue candies is equal to 23​% at 0.01 significance level.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 24​% of them are blue.

The candy company claims that the percentage of blue candies is equal to 23​%.

<u><em>Let p = percentage of blue candies.</em></u>

So, Null Hypothesis, H_0 : p = 23%      {means that the percentage of blue candies is equal to 23​%}

Alternate Hypothesis, H_A : p \neq 23%      {means that the percentage of blue candies is different from 23​%}

The test statistics that would be used here <u>One-sample z proportion test statistics</u>;

                              T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, \hat p = sample proportion of blue colored candies = 24%

           n = sample of colored​ candies = 100

So, <em><u>test statistics</u></em>  =  \frac{0.24-0.23}{\sqrt{\frac{0.24(1-0.24)}{100}}  }

                               =  0.234

The value of z test statistics is 0.234.

<u>Now, at 0.01 significance level the z table gives critical values of -2.5758 and 2.5758 for two-tailed test.</u>

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis.</em></u>

<em />

Therefore, we conclude that the percentage of blue candies is equal to 23​%.

6 0
3 years ago
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