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Katarina [22]
4 years ago
11

A third-degree polynomial function f has real zeros -2, ½, and 3, and its leading coefficient negative. Write an equation for f.

Sketch the graph of f. How many different polynomials functions are possible for f?
Mathematics
1 answer:
Rom4ik [11]4 years ago
8 0
F(x) = k(x+2)(2x-1)(x-3), where k is some constant
= k(2x^3-3x^2-11x+6)
= k(-2x^3+3x^2+11x-6)

k defines some vertical stretch, so there are an infinitely many solutions for f(x).
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MA_775_DIABLO [31]

Answer:

Go with the 2nd choice.

Step-by-step explanation:

When using proportions to solve for unknown quantities, you need to keep the same units on the same side. This means keep "ft" on the top side and "mi" on the bottom side.

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graph the line that passes through the points (-3,-7) and (-2,-7) and determine the equation of the line
Lera25 [3.4K]

Answer:

y = -7

Step-by-step explanation:

y2 - y1 / x2 - x1

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0/1

= 0

y = 0x + b

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3 0
3 years ago
If the function rule is y equals 3x - 4 what is range when the domain is 7?​
nika2105 [10]
Domain is another word for the x value. so, this question just asking us to solve for y when x = 7

first, substitute in x

y = 3(7) -4

and then solve for y

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4 0
2 years ago
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2
Rasek [7]

The factorisation of the given expressions is as follows;

  • a) p²y²– 2py + 1 = (py -1)²
  • b) a²y² -2aby +b² = (ay - b)²

<h3>Factorization using identities</h3>

The given identity is;

  • a²– 2ab + b² = (a – b)²

From the given identity, we can conclude that;

In the expression (a);

  • py represents a in the identity and 1 represents b in the identity.

In the expression (b);

  • ay represents a in the identity and b represents b in the identity.

Hence, the factorised expressions are as represented above.

Read more on factorisation;

brainly.com/question/24371127

8 0
2 years ago
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