Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
Answer:
this a poem or a part of a song?
Step-by-step explanation:
Answer:
Points apply to the given situation:
(a)The puppy will run into the wall after 5 seconds
(b)The slope is -4 ft per second since the puppy is running at a rate of 4 ft per second.
(c)The y-intercept is 20 ft because the puppy is 20 feet away from the wall.
Step-by-step explanation:
We have given,
A puppy is running at a rate = 4 feet per second
A wall is 20 feet away from puppy. That means initially puppy is 20 feet away from the wall.
So, time taken by puppy to reach the wall =
i.e. time take by puppy to reach the wall = = 5 seconds
Now we write the points that apply to this situation:
(a)The puppy will run into the wall after 5 seconds
(b)The slope is -4 ft per second since the puppy is running at a rate of 4 ft per second. {Since the puppy is moving towards the wall that means horizontal distance is decreasing at a rate of -4 feet per second}
(c)The y-intercept is 20 ft because the puppy is 20 feet away from the wall.
Answer:
P = 0.05
Step-by-step explanation:
12 months * 30 days each = 360 days
From 306 days, we have to select 8 days = 360C8 ways(Total ways)
We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways
---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]
Therefore P = Number of ways of selecting each days from different month / Total number of ways
P = 12C8 * 30^8 / 360C8
P = 495 * 656100000000 / 6469697679132645
P = 0.0501985588982791
P = 0.05
Hence the probability that each day is from a different month is 0.05
