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kondaur [170]
3 years ago
7

What is the slope?

Mathematics
1 answer:
Verizon [17]3 years ago
7 0
The slope is -2 or -2/1 
the x intercept is -8 
the y intercept is -4
the equation of the line in slope intercept form is y= -2x-4
the equation of the line in standard form is -2x-4y=0
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-2/7x=4/7 how to check your answer
Ymorist [56]

Answer:

1)Evaluate the left-hand side expression at the given value to get a number.

2)Evaluate the right-hand side expression at the given value to get a number.

3)See if the numbers match.

Sorry if wrong

7 0
2 years ago
Emma needs to divide 7 by 1/2. Which strategy can Emma use to get the answer?
Juliette [100K]

Answer:

14

Step-by-step explanation:

Convert the fraction into a decimal

1/2 = 0.5

Divide

7/0.5 = 14

7 0
3 years ago
If you purchase a dozen bagels, you save 10% If a dozen bagels originally costs $11.50, what is the sale price
KonstantinChe [14]
10 percent of 11.50 is 1.15. Subtract that from 11.50 and you would get 10.35. The sale price would be $10.35
6 0
2 years ago
The length of a rectangle is 8 inches more than three times the width. the perimeter is 88 inches. find the length and width.
Sav [38]
We can say L as length and W as the width 

L= 3w + 8 

The formula for perimeter is 2L + 2W = P. We can substitute L in as "3w+8" to make the equation... 

2(3w+8)+2w=88        Now, we can simplify by distributing the 2 to each term
6w+16+2w=88
8w+16=88               Then subtract 16 from each side..
8w=72
w=9

So the width is 9, so we can substitue that into the previous equation, L = 3w+8. 

L=3(9)+8
L=27+8
L=35, W=9



5 0
2 years ago
The coordinates of the image of line segment RT are R'(-2,-4) and T'(4.4). The image was produced by a dilation with a scale fac
Daniel [21]

Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:

For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:

R = 12R'

R = 12(-2, -4)

R = (-24, -48)

For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:

T = 12T'

T = 12(4, 4)

T = (48, 48)

Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)

6 0
1 year ago
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