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3 years ago

What is the dimensions for a square that has an area of 30 and a perimeter of 34

1 answer:

4 0

A 4-sided thing with area of 30 and perimeter of 34
has these dimensions:

<em> Length = 15</em>
<em> Width = 2</em>

That's no square.

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The population of a town increased by 15% in 2016, and decreased by 5% in 2017. If the population of the town was 60,000 in the

nikdorinn [45]

Answer:

The population of the town at the end of 2017 was 65,550.

Step-by-step explanation:

The population of the town was 60,000 in the beginning of 2016.

In 2016, the total population is increased by 15%.

$60,000\times\frac{15}{100}=9000$

Therefore the population is increased by 9000 and the population of the town at the end of 2016 was

$60,000+9000=69,000$

In 2017, the total population is decreased by 5%.

$69,000\times\frac{5}{100}=3450$

Therefore the population is decreased by 3450 and the population of the town at the end of 2017 was

$69,000-3450=65,500$

Therefore the population of the town at the end of 2017 was 65,550.

3 0

3 years ago

Which expression is equivalent to 10p - 35?

s344n2d4d5 [400]

Answer:

a: $5\left(2p-7\right)$

Step-by-step explanation:

$10p-35$

$5* \:2p-5* \:7$

$5\left(2p-7\right)$

5 0

3 years ago

Read 2 more answers

Convert standard to slope-intercept forms. 1. Standard form: 10x − 7y = −8

garri49 [273]

Answer:

Step-by-step explanation:

-7y = -10x - 8

y = 10/7x + 8/7

8 0

3 years ago

Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

6 0

3 years ago

What's the answer to this?: divide 33 photos into two groups so the ratio is 4 to 7

velikii [3]

total units of ration = 4 +7=11

so, ratio would be (4*33)/11 : (7*33)/11

12 : 21 is the answer.

Did you understand?

5 0

3 years ago

Read 2 more answers