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klemol [59]
3 years ago
11

What is the dimensions for a square that has an area of 30 and a perimeter of 34

Mathematics
1 answer:
Alla [95]3 years ago
4 0

A 4-sided thing with area of 30 and perimeter of 34
has these dimensions:

          <em> Length  =  15</em>
<em>            Width  =  2</em>

That's no square.


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Roscoe rides his bike at least 10 miles but not more than 30 miles. He rides at an average rate of 10.5 miles per hour. The amou
zheka24 [161]

Actually, the domain is the possible set of input values of a function that will make the function fit the specific criteria. In this case, the input value is m, where m is the number of miles that is travelled. The criteria is to travel at least 10 miles but not more than 30 miles, therefore the domain should be:

 

All real numbers from 10 to 30, inclusive

 

(should be real numbers not integer since any fractional number is included in the domain)

 

I cannot figure out why the choices are far from the answer.

3 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
Wendy can wash a car twice as fast as Jason. When they work together, Wendy and Jason can wash a large van in 2 hours. How many
Ugo [173]
X= number of hours would it take Jason to wash the van by himself.
2x=number of hours would it take Wendy to wash the van by herserlf.

<span>we calcaulate the fraction of  work by Jason during one hour </span>

x hours-----------------------------1 work
1 hour----------------------   fraction of work during one hour.

fraction of work during one hour=(1 hour * 1work) / x hours=1/x


we calculate the fraction of work by Wendy during one hour.
2x hours-----------------------------1 work
1 hour----------------------   fraction of work during one hour.

fraction of work during one hour=(1 hour * 1work) / 2x hours=1/2x

We can suggest this equation:
2 hours(fraction of work by Jason during one hour + fraction of work by Wendy during one hour)=1 work

2(1/x + 1/2x)=1

least common multiple=2x
2(2+1)=2x
2(3)=2x
6=2x
x=6/2
x=3

answer: 3 hours would ti take Jason to wash the van by himself.


5 0
3 years ago
What is the value of this expression when b=5?<br><br> 6(2b-4)
Taya2010 [7]
6(2(5) - 4)
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4 0
2 years ago
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Naddika [18.5K]
To get the biggest possible number, use all the symbols at once. 1000+100+10+9+8+7+6+5+4+3+2+1=what?
4 0
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