Work out the smallest integer value of x that satisfies the inequality 4x-3>22. ( I have not learned this question in maths )

Un deposito de agua tiene forma de prisma rectangular con los lados de la base de 25 y 20 metros. Calcula la altura que pueda co

serious [3.7K]

Answer:

La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.

Step-by-step explanation:

Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus 3 dimensiones: longitud*ancho*altura. El volumen se expresa en unidades cúbicas.

En este caso, se conoce la longitud y el ancho, cuyos valores son 25 y 20 metros. A su vez, se sabe que el depósito de agua debe contener 1000 m³. Entonces, siendo:

Volumen= longitud*ancho*altura

Y reemplazando los valores se obtiene:

1000 m³= 25 m* 20 m* altura

Resolviendo:

1000 m³= 500 m²* altura

$altura=\frac{1000 m^{3} }{500 m^{2} }$

altura= 2 m

<u><em>La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.</em></u>

7 0

3 years ago

Santana had a goal to read 50 pages of his

DIA [1.3K]

He read 110 pages i think

5 0

3 years ago

Find the common difference for the sequence below. 1/4, 5/16, 3/8,..

vredina [299]

Answer:

the common difference of the sequence is $(\frac{1}{16})$

Step-by-step explanation:

A sequence of numbers is said to be in arithmetic progression of each term of the sequence has same common difference.

Now, here first term a1 = 1/4

Second term a2 = 5/16

Third term a3 = 3/8

Now, Common difference (d) = a2 - a1 = a3 - a2

Now, a2 - a1 = $\frac{5}{16} - \frac{1}{4} = \frac{5 - 4}{16} = \frac{1}{16}$

Now, a3 - a2 = $\frac{3}{8} - \frac{5}{16} = \frac{6 - 5}{16} = \frac{1}{16}$

Hence, the common difference of the sequence is $(\frac{1}{16})$

5 0

3 years ago

At noon joyce drove to the lake at 30 mph, but she made the long walk back home at 4 mph. how many hours did she walk if she was

lina2011 [118]

By definition we have the following equation:
t = d / v
Where,
t: time
d: distance
v: speed
For this case we have:
d / 30 + d / 4 = 17
Rewriting we have:
2d + 15d = 17 (60)
17d = 17 (60)
d = 60 mi
Then, the walking time is
t = d / v
t = 60/4
t = 15 hours
Answer:
She walked
t = 15 hours

4 0

3 years ago

The probability that a grader will make a marking error on any particular question of a multiple-choice exam is 0.15. If there a

sashaice [31]

Answer:

$P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969$

$P(X \geq 1)= 1-P(X$

$P(X=0)=(nCn)(p)^{0} (1-p)^{n-0}=(1-p)^n$

$P(X \geq 1)= 1-P(X$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.15)$

what is the probability that no errors are made?

For this case means that all the questions were correct so we want this probability:

$P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969$

what is the probability that at least one error made?

For this case we want this probability:

$P(X \geq 1)$

And we can use the complement rule:

$P(X \geq 1)= 1-P(X$

If there are n questions and the probability of a marking error is p rather than 0.15, give expressions for the probabilities of no errors and at least one error

$P(X=0)=(nCn)(p)^{0} (1-p)^{n-0}=(1-p)^n$

$P(X \geq 1)= 1-P(X$

8 0

3 years ago