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Artemon [7]
3 years ago
12

Can you guys help me slove problem 8+-7

Mathematics
2 answers:
Fantom [35]3 years ago
4 0
1

because - plus a bigger positive is positive
bearhunter [10]3 years ago
3 0
If you are talking about 8+(-7) then it Equals one
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If y = -10 -x, find y when x = -2​
arlik [135]

Answer:

y = -8

Step-by-step explanation:

y = -10 - x

y = -10 - (-2)

y = -10 + 2

y = -8

8 0
2 years ago
Read 2 more answers
I don’t understand what to solve.
White raven [17]
Well since it gives you 2 gas stations it wants you to compare prices

Als gas station will be A
At-one will be B

since station A has $3.259/ gallon I assume
and B has $3.199/ gallon

just subtract them

so 3.259 -3.199 = 0.06

gas is less at station B noticeably costs less so thats your first answer

for the next one if you bought gallon of gas at the cheaper station you'd be saving $0.06/gallon since we got the difference from subtracting them.
3 0
3 years ago
A girl successfully made 12 free throws yesterday today she made 150% as a nanny how many successful Fritos did she make today
Bas_tet [7]

Answer:

18 throws

Step-by-step explanation:

Given data

Number of throws= 12

Let us 150% if 12

=150/100*12

=1.5*12

=18 throws

Hence she made 18 throws today

6 0
2 years ago
Which of the following is a fully factored expression of 24x – 56y + 72?
gulaghasi [49]
24x-56y+72

8(3x-7y+9)
7 0
3 years ago
Read 2 more answers
A 20% apple juice drink is mixed with a 100% apple juice drink. The function f(x)=(2)(1.0)+x(0.2)2+x models the concentration of
luda_lava [24]

Answer:

17.5

Step-by-step explanation:

Given that:

20% apple juice drink is mixed with a 100% apple juice drink.

f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}

represents the concentration of apple juice in the drink when x gallons of 20% drink are added to 2 gallons of pure juice.

Also, given that 6 gallons of 20% drink are added to the 2 gallons of pure juice.

To find:

The concentration of apple juice in the drink = ?

Solution:

Given the function:

f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}

and

x=6\ gallons

f(x)=\dfrac{(2)(0.1)+6(0.2)}{2+6}\\\Rightarrow f(x)=\dfrac{0.2+1.2}{8}\\\Rightarrow f(x)=\dfrac{1.4}{8}\\\Rightarrow f(x)=\bold{0.175}

In percentage, the concentration 17.5.

7 0
2 years ago
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