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3 years ago

7

A biologist wants to know the width (w) of a river to properly set instruments for an experiment. From point A, the biologist wa

lks downstream 100 feet and sights to point C. From the sighting it is determined that 0=54°. How wide is the river?

1 answer:

nevsk [136]3 years ago

4 0

Answer:

w = 137.6 ft

Step-by-step explanation:

100 tan 54° = w/100 *100

Simplify w/100*100 = w

w = 100 tan 54°

w = 137.6 ft

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Step-by-step explanation:

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If f(x)=3x^2-5 and g(x)=-2x+5, then f(3)g(3)=

Vladimir [108]

Answer:

(

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)

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)

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x

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2

Explanation:

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Step-by-step explanation:

5 0

2 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

6 0

3 years ago

PLS HELP I DONT UNDERSTAND !

Svetach [21]

Answer:

I think the answer is 24

Step-by-step explanation:

hope its helpful

4 0

3 years ago