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3 years ago

Using compatible numbers to estimate the quotient 358/3

1 answer:

7 0

If you estimate the answer would be 119 because when you divide it the answer is 119.3 so you estimate it to be 119 hope this helps

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A quadratic function f is given F(x)= x^2_4x+6 Express f in standard form ?

Dennis_Churaev [7]

Hey there!

In the equation mentioned,

f represents function.

Hope my answer helps!

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3 years ago

Ethan is responsible to write the minutes for the meeting. During the meeting, he finished writing of the minutes. Before gettin

dolphi86 [110]

11/24
1. 3/8 = 9/24
2. 1/6 = 4/24
3. 9/24 + 4/24 = 13/24
4. 1- 13/24 = 11/24

And that’s if! Hoped this helped :)
These are all the correct steps to get the answer to this problem

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3 years ago

Help please!! Sylvia walked 3/4 miles east from her house to the bank. then she walked 1/3 mile west the gift shop. from the gif

Nostrana [21]

1,320 feet or 1/4 of a mile

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3 years ago

Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are relat

anzhelika [568]

Answer:

(c) Probability that a failure is due to loose keys = 0.2376

(d) Probability that a failure is due to improperly connected or poorly welded wires = 0.078

Step-by-step explanation:

The Whole probability scenario is given for Computer Keyboard failures.

(a) Let F be the event of failure due to faulty electrical connects, P(F) = 0.12

M be the event of failure due to mechanical defects, P(M) = 0.88

LK be the event of mechanical defect due to loose keys, P(LK/M) = 0.27

IA be the event of mechanical defect due to improper assembly, P(IA/M) =0.73

DW be the event of electrical connects due to defective wires,P(DW/F) = 0.35

IC be the event of electrical connects due to improper connections,

P(IC/F) = 0.13 .

PWW be the event of electrical connects due to poorly welded wires,

P(PWW/F) = 0.52

(b) Keyboard failures

Faulty electrical connects Mechanical Defects

P(F) = 0.12 P(M) = 0.88

Defective wires Improper Poorly Loose Keys Improper

P(DW/F)=0.35 Connections Welded wires P(LK/M)=0.27 Assembly

P(IC/F)=0.13 P(PWW/F)=0.52 P(IA/M)=0.73

This is the required tree diagram.

P(LK) =P(LK/M) * P(M) {This means mechanical failure is due to loose

keys}

P(LK) = 0.27 * 0.88 = 0.2376 .

(d) Probability that a failure is due to improperly connected or poorly welded

wires is given by P(IC $\bigcup$ PWW) ;

P(IC $\bigcup$ PWW) = P(IC) + P(PWW) - P(IC $\bigcap$ PWW) { Here P(IC $\bigcap$ PWW) = 0 }

P(IC) = P(IC/F) * P(F) = 0.13 * 0.12 = 0.0156

P(PWW) = P(PWW/F) * P(F) = 0.52 * 0.13 = 0.0676

Therefore, P(IC $\bigcup$ PWW) = 0.0156 + 0.0676 - 0 = 0.078 .

8 0

3 years ago

Solve for a 1/4 (20 - 4a) = 6- a G. No Solution H. All Real Numbers I. -6 J. -6

Margaret [11]

Answer:

THE EQUATION HAS NO SOLUTION!

Step-by-step explanation:

Simplify 1/4 , (1/4 • (20 - 4a)) - (6 - a) = 0 , 3.1 Pull out like factors : 20 - 4a = -4 • (a - 5) , (5 - a) - (6 - a) = 0 , -1 = 0 , 5.1 Solve : -1 = 0, THERES NO SOLUTION MATE TRUST ME!

4 0

3 years ago