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Katyanochek1 [597]
3 years ago
12

Find two consecutive whole numbers that square root of 63 lies between

Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Given:

The number \sqrt{63} lies between two whole numbers.

To find:

The two consecutive whole numbers.

Solution:

The perfect squares of natural numbers are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, ... .

The number 63 lies between 49 and 64.

49

Taking square root on each side, we get

\sqrt{49}

7

Therefore, the number \sqrt{63} lies between two whole numbers 7 and 8.

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9x^2-6x+8=0 what is the fifth step in solving this equation
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Answer:

write the equation as a binomial

Step-by-step explanation:


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3 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

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3 years ago
PLEASSSE help will give brainliest
joja [24]

Answer:

c

Step-by-step explanation:

you divide each side by four to get a=2.5 b=2.5 and c=3

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Answer:

h'(t)= -12

Step-by-step explanation:

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h'(t)=d/dt (-12t + 24 + 6)

h'(t)=d/dt (-12t + 30)

h'(t)=d/dt (-12t) + d/dt (30)

h'(t)= -12+0

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Question 14
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Answer:

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Step-by-step explanation:

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