The hint says that volume of a rectangular solid = l*w*h, where l = length, w = width, and h = height. Use this to solve for the height of the solid by plugging in the numbers you know.
You know that length, l = 2cm, width, w = 8cm, and, *EDITED* volume = 160 cm^3. Plug these values into the equation for volume (the hint) and solve for h, the height:
Volume = lwh
160 = (2)(8)(h)
160 = 16h
h = 10cm
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Answer: The height is 10 cm
Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:
Let the number be
.






The number is 5.
Question 1 might be B. 0.3
Question 2 might be D.TW, TM, CW, CM, HW, HM
I'm not 100% sure though
Answer:
Multiplying and simplifying the term
we get 
Option C is correct option.
Step-by-step explanation:
We need to multiply and simplify: 
Simplifying the term:

While multiplying, the variables with same bases are multiplied: 
In the given question only x^2 and x^4 are variables with same bases, So we get:

So, multiplying and simplifying the term
we get 
Option C is correct option.