Answer: 1/3
<u>Divide</u>
30/90÷30/30=1/3
Since we are simplifying fractions we divide the numerator and the denominator by a number the fraction can go into.
We could use 10 then divide by 3. You can also just divide by 30 and get the answer.
Let's try dividing by 10 then 3!
30/90÷10/10=3/9
3/9÷3/3=1/3
As you can see we still get 1/3 when we divide by 3. Even tho you have to divide twice you still get 1/3. That's all that matters.
P( both allergic) = 0.17*0.17 = 0.0289
P(at least one is allergic) = 1 - P(neither are allergic) = 1 - 0.83^2 = 0.311
Answer:
<h2>width = 6 feet</h2>
Step-by-step explanation:
let l be the length of the rectangle
let w be the width of the rectangle
The statement
The length of a rectangle is 6 feet more than three times the width of the
rectangle is written as
l = 6 + 3w
From the question
l = 24 feet
Substitute the value into the above formula and solve for the width
That's
24 = 6 + 3w
3w = 24 - 6
3w = 18
Divide both sides by 3
w = 6
Therefore
<h3>width = 6 feet</h3>
Hope this helps you
Answer:
2
Step-by-step explanation:
ok so let's start
were starting off with -3/4 and were adding 2 3/4 to that and it's equal to 2 3/4 subtract 3/4
-3/4 + 2 3/4 = 2 3/4 - 3/4
2 3/4 - 3/4 = 2
-3/4 + 2 3/4 = 2
it's 2 my dude or girl i don't know
Putting this as an arithmetic sequence gives:
The sum of the series = 16 x 7 x 7 = 784 m^3 = 784 000 L
The sum of an arithmetic series can be written as:
![S_n=n/2 [2a+(n-1)d] = 784 000 \\n/2[2(150)+(n-1)200] = 784 000 \\n[300+200(n-1)=1 568 000 \\300n+200n^2-200n = 1 568 000 \\200n^2+100n- 1 568 000 = 0 \\2n^2 +n- 15680 = 0 \\n= 88.2...,-88.7](https://tex.z-dn.net/?f=S_n%3Dn%2F2%20%5B2a%2B%28n-1%29d%5D%20%3D%20784%20000%0A%5C%5Cn%2F2%5B2%28150%29%2B%28n-1%29200%5D%20%3D%20784%20000%0A%5C%5Cn%5B300%2B200%28n-1%29%3D1%20568%20000%0A%5C%5C300n%2B200n%5E2-200n%20%3D%201%20568%20000%0A%5C%5C200n%5E2%2B100n-%201%20568%20000%20%3D%200%0A%5C%5C2n%5E2%20%2Bn-%2015680%20%3D%200%0A%0A%5C%5Cn%3D%2088.2...%2C-88.7)
n has to be positive, so we get
n =
<u>88.2 hours (3 s.f.)</u>
