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Nutka1998 [239]
2 years ago
5

During a blizzard, Daniel lost power for 40 hours. His neighbor lost power for 2 days. Whose power was out longer?

Mathematics
1 answer:
andriy [413]2 years ago
8 0

Answer:

his neighbors

Step-by-step explanation:

there are 48 hours in 2 days, which means that his neighbors power was out longer.

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If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
The angle bisector of
klemol [59]
A is correct. Hope my answer helped u :)
6 0
3 years ago
Write the expression 53.7124 x 10^{3} as a single number
mars1129 [50]

Answer:

53712.4

Explanation:

\sf\rightarrow  53.7124\:x\:10^3

  • 10³ = 1000

\sf\rightarrow  53.7124\:x\:1000

\sf\rightarrow  53712.4

6 0
2 years ago
Read 2 more answers
Give the domain and range.
Rzqust [24]

Answer:

c number option is the correct answer

5 0
3 years ago
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What is the volume of a triangular pyramid that is 10 in tall and has a base area of 9 in
Andreas93 [3]
V= 1/3BH
= 1/3( 1/2x9x5)10
= 1/3(45/2) 10
= 75in ^3
6 0
3 years ago
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