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Rzqust [24]
4 years ago
15

Answer to 3+2+(5-1)+5=

Mathematics
1 answer:
otez555 [7]4 years ago
5 0

Answer:

14

Step-by-step explanation:

3 + 2 + (5 - 1) + 5

Always solve the ones inside the parentheses first.

3 + 2 + (4) + 5

5 + 4 + 5

9 + 5

= 14

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3 years ago
Help! See the question below!
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It’s the 3rd problem:)
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3 years ago
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According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h
andreyandreev [35.5K]

Answer:

The graph f(x)=x^2-4x+3  has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph f(x)=x^2-4x+3

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation f(x)=x^2-4x+3  the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, f(x)=x^2-4x+3=0

This is a quadratic equation, x^2-4x+3=0

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0

\Rightarrow x(x-1)-3(x-1)=0

\Rightarrow (x-3)(x-1)=0

Using zero product property, a\cdot b=0 \Rightarrow a=0\ or \ b=0

\Rightarrow (x-3)=0 or \Rightarrow (x-1)=0

\Rightarrow x=3 or \Rightarrow x=1

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph f(x)=x^2-4x+3  has two zeros  namely 3 and 1.  

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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How to solve for a, b,
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It looks like the length of a and b should be the same. You can use the Pythagorean theorem (only works with right triangles):

a² + b² = c² (c is the hypotenuse or the longest side of the triangle, a and b are the other side lengths of the triangle)

a² + (4)² = (5)²

a² + 16 = 25

a² = 9

a = 3

a and b have a length of 3

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3 years ago
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