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amm1812
3 years ago
11

Suppose a railroad rail is 4 kilometers and it expands on a hot day by 15 centimeters in length. Approximately how many meters w

ould the center of the rail rise above the​ ground?
Mathematics
1 answer:
dsp733 years ago
3 0
Ddjdudjdjdjddjdjdjdc
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Which of the following expression is not equivalent to -4.5 times -8?
torisob [31]

(8)(-4.5) is not equivalent because 8 times -4.5 results in negative value

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3 years ago
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Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note
Viktor [21]

a. Recall that

\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C

For |x|, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

By integrating both sides, we get

\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

If x=0, then

\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0

so that

\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

We can shift the index to simplify the sum slightly.

\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n

b. The power series for x\ln(1-x) can be obtained simply by multiplying both sides of the series above by x.

\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n

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\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)

\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}

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The formula for the volume of a sphere is a power function:
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Answer:

r≥0

V(r) ≥0

Step-by-step explanation:

V(r) = 4/3 * Pi* r^3

The domain is the input values for r

The radius cannot be less than 0  but can be any number bigger than 0

What is the domain of the function in this situation?

r≥0

The range is the output values for the function or the volume

The volume must be greater than or equal to zero

V(r) ≥0

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The answer on APEX would be $2430
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Which equation represents the graphed function?
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Answer:

Step-by-step explanation:

6x

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