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Gnom [1K]
3 years ago
14

A rectangle is four times as long as it is wide. The perimeter is 40 cm. Find the length of each side.

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

W=4 l=16

Step-by-step explanation:

Let w = width

Let l = length

Since the length is 4 times the width, l=4w

Perimeter of rectangle = 2l + 2w

= 2(4w)+2w

=10w

The perimeter of the rectangle =40, so

40=10w and w=4

Plug w into the length equation : l=4w=4(4)=16

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\tt Step-by-step~explanation:

To solve, we have to look for a pattern.

\tt Step~1:

When you see pyramids like these, they usually tell you to add/multiply the two numbers to get a third number that goes on top. Here, we can see 3 and 4 on the bottom left hand corner. The third number on top of both 3 and 4 is 7.  3 + 4 = 7. Let's check 4 and 5, the middle two numbers. 4 + 5 = 9, and that number is on top of 4 and 5. Therefore, we can confirm that this is an addition pyramid.

\tt Step~2:

Since 7 + 9 is 16 and 9 + 8 is 17, all we need to do in order to get the final number is to add 16 to 17.

\tt 16 + 17 =33

\large\boxed{\tt Our~final~answer: ~33}

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Read 2 more answers
Samples of a cast aluminum part are classified on the basis of surface finish (in microinches) and edge finish. The results of 1
liubo4ka [24]

Answer:

a) P (A)= 88/102= 0.8627

(b) P (B)=  89/102= 0.8725

c) P (A`) =  14/102 = 0.1372

(d) P (A∩B) = 84/102 =0.8235

(e) P(AUB)= 93/102 = 0.9117

(f)P (A`UB) = 98/102= 0.96078

Step-by-step explanation:

                                                                   edge                  

                                                  finish excellent       good           Total

<u>(A )surface finish excellent            84                      4                  88</u>

good                                    ( B) ⇵    5                       9                  14

Total                                               89                      13                102

a) Upper P left-parenthesis Upper A right-parenthesis equals

P (A)= 88/102= 0.8627

All the elements of set A = 84+4= 88

(b) Upper P left-parenthesis Upper B right-parenthesis equals

P (B)=  89/102= 0.8725

All the elements of set B = 84+5= 89

c) Upper P left-parenthesis Upper A prime right-parenthesis equal

P (A`) =  14/102 = 0.1372

All the elements of Universal set U which are not elements of set A = 102- 88= 14

(d) Upper P left-parenthesis Upper A intersection Upper B right-parenthesis equals

P (A∩B) = 84/102 =0.8235

Only those elements of set A and set B which are common

(e) Upper P left-parenthesis Upper A union Upper B right-parenthesis equals

P(AUB)= 93/102 = 0.9117

Totalling elements of set A and B= 88+5= 93

(f) Upper P left-parenthesis Upper A prime union Upper B right-parenthesis equals

P (A`UB) = 98/102= 0.96078

All the elements of Universal set U which are not elements of set A and the elements of Set B = 5+9+ 84= 98

6 0
3 years ago
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