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Harrizon [31]
3 years ago
9

Consider a function that describes how a particular cars gas mileage depends on its speed. What would be an appropriate domain f

or this function?
Mathematics
2 answers:
Elina [12.6K]3 years ago
8 0

gas mileage = k*s, where k is a constant of proportionality and s is the speed. Unfortunately, this does not take into account the fact that the engine consumes fuel even when the car is not moving.


Here it makes most sense to regard {0, S} as the domain for this function. Here, S would represent the car's top speed.


erica [24]3 years ago
8 0

Answer:

a

Step-by-step explanation:

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Is 7/20 equal to 0.35
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Answer:

yes it is

Step-by-step explanation:

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Find the inequality represented by the graph ​
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Question is on photo please help but i thnk its 4
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Read 2 more answers
Find the Prime Factorization of -165
Ghella [55]

Answer:

(-1)(11)(3)(5)

Step-by-step explanation:

First off:  -165 separates into the factors (-1) and (165).  Next, we divide 165 by 15, obtaining 15(11).

So far, we have (-1)(11)(15).

15 is still factorable.  We get:

(-1)(11)(3)(5), which is the desired prime factorization of -165.

6 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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