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Andrews [41]
3 years ago
12

The dimensions of the fountain cup are as follows:

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

Volume of fountain cup in gallons = 1,192.5 gallon (Approx.)

Step-by-step explanation:

Given:

Height of Frustum = 8 feet

Diameter of top = 6 feet

Diameter of base = 4 feet

Find;

Volume of fountain cup in gallons

1 cubic foot = 7.5 gallons

Computation:

Radius of top = 6 / 2 = 3 feet

Radius of base = 4 / 2 = 2 feet

Volume of fountain cup in gallons = (πh/3)[R² + r² + Rr]

Volume of fountain cup in gallons = [(3.14)(8)/3)[3² + 2² + (3)(2)]

Volume of fountain cup in gallons = [8.37)[9 + 4 + 6]

Volume of fountain cup in gallons = [8.37)[19]

Volume of fountain cup in gallons = 159.03

Volume of fountain cup in gallons = 159 feet³

Volume of fountain cup in gallons = 159 x 7.5

Volume of fountain cup in gallons = 1,192.5 gallon (Approx.)

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Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


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