All categories

3 years ago

2HgO(s) --> 2Hg(l) + O2 (g)

1 answer:

5 0

Percent yield describes the amount of product produced in a reaction relative of the amount of reactant you started with. In this question, you begin with 8.74 grams of HgO, and dividing this by it’s formula mass of 216.58g (200.59 for Mercury and 15.99 for Oxygen), we find that this amount of HgO is 0.0404 moles.

You end with 6.42 grams of Hg, or 0.032 moles, when divided by its formula weight of 200.59g.

The percent yield is calculated by dividing the number of moles of product by the number of moles of reactant and multiplying by 100, so the percent yield is:

0.032/0.0404 = 0.792 x 100 = 79.2%.

The reaction proceeds at 79.2% efficiency.

You might be interested in

List the number of each type of atom on the right side of the equation h2so4(aq)+bacl2(aq)→baso4(s)+2hcl(aq) enter your answers

DiKsa [7]

Answer is: 2H, 1S, 4O, 1Ba, 2Cl or 2,1,4,1,2.
Number of atoms must be the same on left and right side of balanced chemical reaction according to the law of conservation of mass or principle of mass conservation.
There are two hydrogen atoms, one sulfur atom, four oxygen atoms, one barium atom and two chlorine atoms in this chemical reaction.

3 0

3 years ago

Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete dissociation of

Serhud [2]

Answer: 0.17 m $CH_3COONH_4$ : Highest freezing point

0.20 m $CoSO_4$ : Second lowest freezing point

0.18 m $MnSO_4$ : Third lowest freezing point

0.42 m ethylene glycol: Lowest freezing point

Explanation:

Depression in freezing point is a colligative property which depend upon the amount of the solute.

$\Delta T_f=i\times k_f\times m$

where,

$\Delta T_f$ = change in freezing point

i= vant hoff factor

$k_f$ = freezing point constant

m = molality

a) 0.17 m $CH_3COONH_4$

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i =2 for $CH_3COONH_4$ , thus total concentration will be 0.34 m

b) 0.18 m $MnSO_4$

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for $MnSO_4$ , thus total concentration will be 0.36 m

c) 0.20 m $CoSO_4$

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for $CoSO_4$ , thus total concentration will be 0.40 m

d) 0.42 m ethylene glycol

For non electrolytes undergoing no dissociation, vant hoff factor is equal to 1 . Thus i = 1 for ethylene glycol, thus concentration will be 0.42 m

The more is the concentration, the highest will be depression in freezing point and thus lowest will be freezing point.

4 0

3 years ago

One way to increase the rate of a reaction occurring in solution is to stir the solution. How does this increase the rate of the

riadik2000 [5.3K]

A. It increases the number of collisions between molecules.

I hope this helps :)

7 0

3 years ago

Read 2 more answers

Why do scientists use the scientific method?

xeze [42]

Answer:

Scientists use the scientific method because it is evidence-based, standardized and objective in conducting experiments. The scientific method allows scientists to stick to facts and to avoid the influence of preconceived notions and personal biases in research processes, improving the credibility of research findings.

Explanation:

4 0

3 years ago

what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.

In-s [12.5K]

Answer:

$\boxed{\text{C. 11.2 L}}$