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vichka [17]
3 years ago
12

For the Heisenburg uncertainty principle, where did the 4 pi come from in the equation, which is "x times p is greater than or e

qual to h divided from 4 pi"?
Chemistry
1 answer:
Setler [38]3 years ago
5 0
That factor appears when you actually do the quite complex maths that lead to the principle; it's quantum mechanics, and it's not something that can be shown easily.

What is important to note is that this factor \frac{1}{4\pi}is not important. What is important is that the uncertainty \Delta x\Delta p_x is approximately of the order of \hbar=\frac{h}{2\pi}, which is a characteristic value that appears in many (most) formulas dealing with quantum mechanics.
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Given the following chemical equation, how many moles of carbon are necessary to react with 5.52 moles of SO2?5C(s) + 2SO2 (g) -
laila [671]
The ratio between C and SO2 is 5:2 So....
take 5.52 * 5 / 2 = 13.8 mol C needed
7 0
3 years ago
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Which one is a Synthesis reaction?​
sveta [45]

Answer:

the second one is synthesis reaction

3 0
2 years ago
Are bonds broken or formed, throughout each phase change present on a heating<br> curve?
Blababa [14]

Answer:

During a phase change no chemical bonds are broken. Atoms are not rearranged because a phase change is a physical change rather then a chemical change. However, intermolecular forces are almost entirely removed from the liquid since the intermolecular forces are what cause the liquid to be a liquid.

Explanation:the nature of the intermolecular forces (IMF) will not change when the state changes from solid to liquid, however, the number of IMF changes.

5 0
2 years ago
The first-order reaction, so2cl2 → so2 + cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 k. what percentage of the init
Svetradugi [14.3K]
For the 1st order reactions,rate constant (k) is mathematically expressed as

k = \frac{2.303}{t}log \frac{Co}{Ct}
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'

Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s

Therefore, we have
</span>2.20 × 10^-5 = \frac{2.303}{7200}log \frac{100}{Ct}
∴ log\frac{100}{Ct} = 0.06877
∴, \frac{100}{Ct} = 1.1716
∴, Ct = 85.35%

Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
4 0
3 years ago
Why does potassium chloride crystallises out of solution?
kompoz [17]

Answer:

R kelly math convinced me that macaroni noodles tastes like butt

Explanation:

R kelly - way of thinking

12 = 16

13 = 18

5 = 42

3 = 21

11 = 67

7 0
3 years ago
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