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likoan [24]
3 years ago
14

what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.

33.6L B. 44.8L C.11.2L D. 22.4 L
Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

\boxed{\text{C. 11.2 L}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?;         T₂ = 136.58 K

Calculations:

\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}

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prohojiy [21]

Answer:

The reaction will move to the left.

Explanation:

  • For the reaction:

<em>Ba(OH)₂ = Ba²⁺ + 2OH⁻,</em>

<em>Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.</em>

  • If H⁺ ions are added to the equilibrium:

H⁺ will combine with OH⁻ to form water.

<em>So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.</em>

<em />

<em>According to Le Châtelier's principle: </em>when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

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<em>So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.</em>

5 0
3 years ago
How long would it take for 1.50 mol of water at 100.0 ∘c to be converted completely into steam if heat were added at a constant
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To determine the time it takes to completely vaporize the given amount of water, we first determine the total heat that is being absorbed from the process. To do this, we need information on the latent heat of vaporization of water. This heat is being absorbed by the process of phase change without any change in the temperature of the system. For water, it is equal to 40.8 kJ / mol.

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Given the constant rate of 19.0 J/s supply of energy to the system, we determine the time as follows:

Time = 61.2 kJ ( 1000 J / 1 kJ ) / 19.0 J/s = 3221.05 s
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<h2> refer the attachment</h2>

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slega [8]

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