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likoan [24]
3 years ago
14

what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.

33.6L B. 44.8L C.11.2L D. 22.4 L
Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

\boxed{\text{C. 11.2 L}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?;         T₂ = 136.58 K

Calculations:

\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}

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Need help FAST! Will rate 5
evablogger [386]

If 28.4 g of HgO decomposes and produces 2.0 g of oxygen, then 26 grams of Hg is produced.

<h3>What is decomposition reaction?</h3>

Decomposition reactions occur when complex chemical entities split apart into smaller components. Decomposition reactions often demand energy input.

There are three different kinds of breakdown reactions: thermal, photolytic, and electrolytic.

Mass_{reactant = Mass_{product}

Mass_{mercury oxide = Mass_{mercury} + mass_{oxygen}

28g =        mass_{mercury} + 2g

   mass_{mercury} = 26g

Thus, 28.4 g of HgO decomposes and produces 2.0 g of oxygen, then 26 grams of Hg is produced.

percentage mass_{mercury} = \frac{mass_{mercury}}{mass_{mercury}oxide}  X 100%

= 26g/28g

= 93%

thus  93% is the percent by mass of Hg present in HgO.

To learn more about Decomposition reaction, refer to the below link:

brainly.com/question/14112196

# SPJ1

4 0
1 year ago
Determine the empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass.
vagabundo [1.1K]

The empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass is C_3H_6S.

<h3>What is the empirical formula?</h3>

An empirical formula tells us the relative ratios of different atoms in a compound.

We need to calculate the number of moles

Number of a mole of carbon =

48.6 g X (\frac{1 mole }{ 12.0107 g}) =4.05 mole

Number of a mole of hydrogen =

8.2g X (\frac{1 mole}{.00784g}) =8.14 mole

Number of moles of sulphur =

43.2g X (\frac{ mole}{32.065g}) = 1.35 mole

Dividing each mole using the smallest number that is divided by 1.35 moles.

Carbon= \frac{4.05 mole }{1.35 mole} =3

Oxygen= \frac{8.14 mole}{1.35 mole} =6

Sulfur= \frac{1.35 mole}{1.35 mole} =1

Empirical formula is C_3H_6S

Learn more about empirical formula here:

brainly.com/question/14044066

#SPJ1

4 0
2 years ago
Convert a pressure of 0.0248 mm Hg to the equivalent pressure in pascals (Pa).
drek231 [11]

Answer is 3.306 Pa.


<em>Explanation:</em>


This is a simple unit conversion problem.

1 atm = 760 mmHg = 101325 Pa


Hence,

    0.0248 mmHg = (101325 Pa / 760 mmHg) x 0.0248 mmHg

                           = 3.306 Pa


Pressure can be measured by using many units such as atm, Pa, torr, bar, cmHg, mmHg and so on.


The relationships among those units as follows

1 atm = 101325 Pa = 1.01325 bar = 760 torr, 760 mmHg = 76 cmHg

5 0
3 years ago
Match the description to the type of mixture.
Softa [21]

Answer:

1-homo

2-hetero

3-hetero

4-homo

Explanation:

7 0
2 years ago
Explain why can two nonmetals bond together, but two metals cannot? A) Metals will only form covalent bonds. B) Nonmetals can sh
erma4kov [3.2K]

Answer: C) Non-metals can share pairs of electrons and form covalent bonds

Explanation: The principal reason why it is non-metals that can form covalent bonds is because of their electronegativities. Electronegativity is the tendency of an atom to attract electrons towards itself.

The participating atoms in a covalent bond have to be able to hold the shared electron in place & it is this attraction towards the centre of each participating atom that holds the electrons in place. Metals aren't electronegative, they don't attract electrons towards each other, they'd rather even push the electrons away from themselves (electropositive) to be stable. The closest concept of metals to shared electrons is in metallic bonding, where metals push and donate their valence electrons to an electron cloud which is free to move around the bulk of the metallic structure. But this is nowhere near the type of bonding that exist in covalent bonds.

4 0
3 years ago
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