Question

what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.33.6L B. 44.8L C.11.2L D. 22.4 L

Answer 1

Answer:

$\boxed{\text{C. 11.2 L}}$

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?;         T₂ = 136.58 K

Calculations:

$\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}$