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3 years ago

What’s the answer??? Answer fast please

Mathematics

2 answers:

postnew [5]3 years ago

5 0

Answer:

300 cm2

Step-by-step explanation:

Volume = length x width x height

expeople1 [14]3 years ago

4 0

Answer:

Volume=300cm^3

Step-by-step explanation:

formula:

Volume=length x width x height

therefore, 5 x 4 x 15 = 300

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Evaluate.....that.....idk how to write/say it lol

denis-greek [22]

Answer:

Step-by-step explanation:

6 0

3 years ago

Could you pleaseee help me

vladimir1956 [14]

$3.6 \times 10^{14} \times 8 \times 10^{10}$

$= 3.6 \times 8 \times 10^{14 + 10}$

$= 28.8 \times 10^{24}$

$= 2.88 \times 10^{25}$

3 0

4 years ago

In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct

kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

$P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279$

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

$=(0.93\times0.03)+(0.10\times0.97)\\=0.1249$

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

$P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234$

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0

3 years ago

Which statement about skew Lines and parallel lines is true

Nina [5.8K]

Skewlines have opposite reciprocal slopes ,and parallel lines have opposite reciprocal slopes

8 0

3 years ago

Solve each of the following systems of equations by substitution

Delvig [45]

Answer:

1) The solution to the given equations is (3,6)

2) The solution to the given equations is (7,-1)

3) The solution to the given equations is (6,5)

Step-by-step explanation:

1) Given equations are $x+y=5\hfill (1)$

and $x=1+y\hfill (2)$

To solve the given equations by substitution method :

From equation (2) we have the value x=1+y

Substitute the value of x=1+y in equation (1) we get

(1+y)+y=5

1+y+y=5

1+2y=5

2y=5-1

2y=4

$y=\frac{4}{2}$

Therefore y=2

Now substitute the value of y=2 in equation (2) we get

x=1+y

x=1+2

Therefore x=3

The solution is (3,6)

2) Given equations are $2x+3y=11\hfill (1)$

and $x+y=6\hfill (2)$

To solve the given equations by substitution method :

From equation (2) we have the value x=6-y

Substitute the value of x=6-y in equation (1) we get

2(6-y)+3y=11

12-2y+3y=11

y=11-12

Therefore y=-1

Now substitute the value of y=-1 in equation (2) we get

x+(-1)=6

x=6+1

Therefore x=7

The solution is (7,-1)

3) Given equations are $x-y=1\hfill (1)$

and $6x-7y=1\hfill (2)$

To solve the given equations by substitution method :

From equation (1) we have the value x=1+y

Substitute the value of x=1+y in equation (2) we get

6(1+y)-7y=1

6+6y-7y=1

-y=1-6

Therefore y=5

Now substitute the value of y=5 in equation (1) we get

x-5=1

x=1+5

Therefore x=6

The solution is (6,5)

8 0

3 years ago