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Vera_Pavlovna [14]
3 years ago
11

If I am 17 years old and my sophomore junior or senior in high school

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

I'm 17 and I'm in my Junior year of high school.
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Help please this is for inequality math!! n + 7 < - 3
stealth61 [152]

Answer:

n < -10

Step-by-step explanation:

n+7 < -3

subtract 7 from both sides

n+7-7 < -3-7

n < -10

4 0
3 years ago
Select all quantities that are proportional to the diagonal length of a square.
horsena [70]

Answer:

B. Perimeter of a square and

C. Side length of a square​

Step-by-step explanation:

if n= side length of square then

  • Area of square is n^{2}
  • Perimeter of a square is 4×n
  • diagonal length of a square is \sqrt{2} × n

Thus,

Perimeter of square can be expressed as

2\sqrt{2}×diagonal length of a square

Side length of a square can be expressed as

\frac{1}{\sqrt{2} }×diagonal length of a square

but Area of square is

\frac{1}{\sqrt{2} }×n×diagonal length of a square

As a Result,  Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>

5 0
3 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
If EF=2x-12, FG= 3x-15, and EG=23, find values of x, EF, and FG
velikii [3]

we have that


*-------------------------*--------------------------------*

E                            F                                     G


EF=2x-12

FG= 3x-15

EG=23


we know that


EF + FG = EG


so

[2x - 12] + [3x - 15] = 23 simplify

5x - 27 = 23 add 27 to both sides

5x = 50 divide both sides by 5

x = 10

EF=2x-12-------> EF=2*10-12-------> EF=8

FG= 3x-15------> FG=3*10-15------> FG=15



therefore


the answer part a) is

the value of x is 10


the answer part b) is

the value of EF is 8


the answer part c) is

the value of FG is 15

6 0
3 years ago
What is the solution to this systems of liner equations y-x=6 y+x=-10
3241004551 [841]
The solution is the point where the two lines intersect (are equal) so y=y and we can say:

6-x=-10-x  upon adding x to both sides:

6=-10

This is never true so there is no solution to this system of equations.  And for this to be true the two lines must be parallel and have different y-intercepts...
3 0
3 years ago
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