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3 years ago

5/8 and 6/14 as a decimal

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

5/8= 0.625

6/14= 0.42

Step-by-step explanation:

5 divided by 8

6 divided by 14

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Maria invests $6,154 in a savings account with a fixed interest rate of 8% compounded continuously. What will the account balanc

Vitek1552 [10]

Answer:

$13,695.98

Step-by-step explanation:

We can use the continuous compound interest formula to solve:

$A = Pe^{rt}$

P = principal amount

r = interest rate (decimal)

t = time (years)

First, lets change 8% into a decimal:

8% -> $\frac{8}{100}$ -> 0.08

Now, lets plug in the values:

$A=6,154e^{0.08(10)}$

$A=13,695.98$

The account balance after 10 years will be $13,695.98

3 0

3 years ago

The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

hoa [83]

Answer:

8 packs of bottled water and 14 packs of candy bars

Step-by-step explanation:

Provided,

Each pack of water bottles = 35 bottles

Each pack of candy = 20 candy

Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,

Purchase quantity of candy packs shall be more than the pack of water bottles.

Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.

In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.

Accordingly

Option 3

8 packs of water bottle = $8 \times 35 = 280 \ water\ bottles$

14 packs of candy = $14 \times 20 = 280 \ candies$

Since the quantities of water bottles and candies are same this is an opt answer.

6 0

3 years ago

Read 2 more answers

What is <img src="https://tex.z-dn.net/?f=12%20%7B%3F%7D%5E%7B2%7D%20%20%5C%5C%20" id="TexFormula1" title="12 {?}^{2} \\ "

marin [14]

$a^n=\underbrace{a\cdot a\cdot a\cdot ...\cdot a}_{n}\\\\12^2=\underbrace{12\cdot12}_{2}=144$

8 0

3 years ago

83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi

arlik [135]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

Step-by-step explanation:

Information given

$\bar X=32.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom given by:

$df=n-1=8-1=7$

The confidence level is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.