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Nina [5.8K]
3 years ago
9

Please help me simplify 9x-3(2+4x)=

Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0
Hi

9x - 3(2+4x) = 9x-3(2)-3(4x) = 9x-6-12x = 9x-12x-6
9x - 3(2+4x) = -3x-6

Answer: -3x-6 
denis23 [38]3 years ago
4 0
solution

1) <span>Expand
</span><span>9x−6−12x

2) </span><span>Gather like terms
</span><span>(9x−12x)−6

3) </span> <span>Simplify
</span><span><span>−3x−6</span></span>
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A student is making cookies for a bake sale. He sells 8 snickerdoodles and 12 chocolate chip
lions [1.4K]

Answer:

Snickerdoodles are 0.22$ each and chocolate chip are 0.43$ each

Step-by-step explanation:

using the information in the problem, you can make 2 separate equations: 8x+12y=6.92 and 5x+5y=3.25, let x= the cost of a snickerdoodle and y= the cost of a chocolate chip cookie.

With the 2 equations, we can isolate the y variable of the first equation and simplify which will give us y= -2/3x +6.92/12.

You can now take that equation and plug it into equation number 2:

5x+5(-2/3x + 6.92/12)=3.25.

solve that equation by multiplying 5 through the brackets: 5x-10/3x+34.6/12=3.25

add common terms: 5/3x=4.4/12

find the value of x, you will get x=0.22

plug the value of x (0.22) into one of your equations and solve for the y-value

8 0
3 years ago
Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.
melamori03 [73]

Answer:

a) 0.8413

b) 421

c) P_{95} = 189.675

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of  IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(IQ scores at most 180)

P(x < 180)

P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 180) = 0.8413 = 84.13\%

b) Number of the members of the club have IQ scores at most 180

n = 500

\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95  

Calculation the value from standard normal z table, we have,  

P(z < 1.645) = 0.95

\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675  

P_{95} = 189.675

8 0
3 years ago
Given the sequence rn defined recursively below, find r3. r1rn=2=−rn−1+n−2
kifflom [539]

Answer:

r_3=3

Step-by-step explanation:

Given:

r_1=2\\r_n=-r_{n-1}+n-2

We want to find the value of r_3 .

\\r_2=-r_{2-1}+2-2\\r_2=-r_1\\r_2=-2\\\\r_3=-r_{3-1}+3-2\\r_3=-r_{2}+1\\r_3=-(-2)+1\\r_3=2+1\\r_3=3

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3 years ago
What is 4.2e+16 written out?
worty [1.4K]
42000000000000000



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3 years ago
A social psychologist interested in cultural differences compared women of two ethnic groups on a Role Approval Index on which h
Levart [38]

Answer:

a. 5.26

Step-by-step explanation:

As, the standard deviation of the distribution of the difference between mean is 0.76 so the t score will be simply calculated by dividing the difference of means by standard deviation of the distribution of the difference between mean as hypothesized difference is zero.

t score=Xbar A- Xbar B/Sd of difference of means

t score=55-51/0.76

t score=4/0.76=5.26

3 0
3 years ago
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