Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
I would say that you cannot answer the question if you dont know either the X-value or Y-value. You need to know at least one of them to figure out the other.
Question:
What is the equation for the following statement,"One-half of a number decreased by 3 is 21.
Answer:
<em>half the number = x/2 </em>
<em>decreased by 3 </em>
<em>(x/2) -3 =21</em>
<em>=48</em>
Hope this helps you understand
Answer:
x = 24
Step-by-step explanation:
The given line y = 3 is a horizontal line with slope zero (0).
We wish to find the equation of a line that is perpendicular to y = 3. Such a line would be a vertical one. Vertical lines do not have slopes defined (due to division by zero).
Thus the general form of the equation of this new line is x = c.
This new line passes through (24, -56). Thus, x must be 24: x = 24
