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3 years ago

7TH GRADE MATH EASY (BEST ANSWER)

2 answers:

6 0

Comlpenentary angles add to 90 degrees

angle3+angle4=90
angle4=49
angle3+49=90
minus 49 both sides
angle3=41

angle3=41 degrees

enot [183]3 years ago

4 0

<3 is 41 because complementary angles add up to 90.

You might be interested in

what is the best point estimate for the population's standard deviation if the sample variance is 49.7? round your answer to one

Vinvika [58]

Using the relation between standard deviation and variance it is concluded that the standard deviation for the population for the given variance is 7.1

<h3>What is the relation between standard deviation and sample variance? </h3>

In statistics, the two most crucial metrics are variance and standard deviation. While the variance is a measurement of how data points vary from the mean, standard deviation is a measure of the distribution of statistical data.

The square root of the variance yields the standard deviation, i.e.

Standard deviation = $\sqrt{variance$

Given that sample, the variance is 49.7 and we have to calculate the standard deviation.

Standard deviation (σ) = $\sqrt{variance$

= $\sqrt{49.7}$

= 7.0498

=7.1

Hence, the standard deviation for the population for the given variance is 7.1

To know more about the relation between standard deviation and variance, visit:

brainly.com/question/10687815

#SPJ4

3 0

1 year ago

Kids bought a package with 2 9/ 16 lb of ground meat to make hamburgers he was he has 2/5 pound of ground meat left about how ma

poizon [28]

Answer:

The quantity of ground meat he use for hamburgers is 2 $\frac{13}{80}$ pounds

Step-by-step explanation:

Given as :

The total quantity of ground meat bought to make hamburgers = 2 $\frac{9}{16}$

Or, The total quantity of ground meat bought to make hamburgers = $\frac{41}{16}$ pound

The quantity of ground meat left after use = $\frac{2}{5}$ pound

Now, let The quantity of ground meat used for hamburgers = x pound

So, x = The total quantity of ground meat bought - The quantity of ground meat left

Or, x = $\frac{41}{16}$ pound - $\frac{2}{5}$ pound

Or, x = $\frac{205-32}{80}$ pound

I.e x = $\frac{173}{80}$

∴ x = 2 $\frac{13}{80}$ pounds

Hence The quantity of ground meat he use for hamburgers is 2 $\frac{13}{80}$ pounds . Answer

7 0

4 years ago

Help on this question

Dimas [21]

The answer is d. DFG

6 0

4 years ago

Pls help me guys! This is super hard

Mashcka [7]

I count 4 green stars and 6 red stars

ratio of green to red would be
4 green : 6 red

4:6

if you divide both numbers by 2, cause theyre both even

2:3

6 0

3 years ago

Read 2 more answers

Given that f(x) = √(ax + 1) , with x ≥ -1/a and a > 0

padilas [110]

Answer:

$\displaystyle 7$

Step-by-step explanation:

first thing I assume by f~¹ you meant $f^{-1}$ however

we want to find a²+3x-3 for the given condition. with the composite function condition we can do so

Finding the inverse of f(x):

$\displaystyle f(x) = \sqrt{ax + 1}$

substitute y for f(x):

$\displaystyle y= \sqrt{ax + 1}$

interchange:

$\displaystyle x= \sqrt{ay + 1}$

square both sides:

$\displaystyle ay + 1 = {x}^{2}$

cancel 1 from both sides:

$\displaystyle ay = {x}^{2} - 1$

divide both sides by a:

$\displaystyle y = \frac{{x}^{2} - 1 }{a}$

substitute f^-1 for y:

$\displaystyle f ^{ - 1} (x) = \frac{{x}^{2} - 1 }{a}$

finding the inverse of g(x):

$\displaystyle g(x) = \frac{x + 1}{x}$

substitute y for g(x)

$\displaystyle y= \frac{x + 1}{x}$

interchange:

$\displaystyle \frac{y + 1}{y} =x$

cross multiplication

$\displaystyle y + 1= xy$

cancel 1 from both sides

$\displaystyle y - xy= - 1$

factor out y:

$\displaystyle y(1 - x)= - 1$

divide both sides by 1-x:

$\displaystyle y= - \frac{1}{ 1 - x}$

substitute g^-1 for y:

$\displaystyle g ^{ - 1} (x)= - \frac{1}{ 1 - x}$

remember that

$\displaystyle (f \circ g)x = f(g(x))$

therefore we obtain:

$\rm \displaystyle (f ^{ - 1} \circ g ^{ - 1} ) (3) = \frac{{ \bigg(- \dfrac{1}{1 - 3} } \bigg)^{2} - 1 }{a}$

since (f~¹•g~¹)(3)=-⅜ thus substitute:

$\rm \displaystyle \frac{{ \bigg(- \dfrac{1}{1 - 3} } \bigg)^{2} - 1 }{a} = - \frac{3}{8}$

simplify parentheses:

$\rm \displaystyle \frac{{ \bigg( \dfrac{1}{2} } \bigg)^{2} - 1 }{a} = - \frac{3}{8}$

simplify square:

$\rm \displaystyle \frac{{ \dfrac{1}{4} } - 1 }{a} = - \frac{3}{8}$

simplify substraction:

$\rm \displaystyle \frac{ - \dfrac{3}{4} }{ a}= - \frac{3}{8}$

simplify complex fraction:

$\rm \displaystyle - \dfrac{3}{4a} = - \frac{3}{8}$

get rid of - sign:

$\rm \displaystyle \dfrac{3}{4a} = \frac{3}{8}$

divide both sides by 3:

$\rm \displaystyle \dfrac{1}{4a} = \frac{1}{8}$

cross multiplication:

$\rm \displaystyle 4a= 8$

divide both sides by 4:

$\rm \displaystyle \boxed{ a= 2}$

as we want to find a²+3a-3 substitute the got value of a:

$\displaystyle {2}^{2} + 3.2 - 3$

simplify square:

$\displaystyle 4 + 3.2 - 3$

simplify multiplication:

$\displaystyle 4 +6 - 3$

simplify addition:

$\displaystyle 10 - 3$

simplify substraction:

$\displaystyle 7$

and we are done!

7 0

3 years ago

​ 7TH GRADE MATH EASY (BEST ANSWER)

7TH GRADE MATH EASY (BEST ANSWER)